![\bf \textit{sum of all interior angles in a polygon}\\\\ S=180(n-2)~~ \begin{cases} n=\textit{number of sides}\\[-0.5em] \hrulefill\\ n=8 \end{cases}\implies S=180(8-2) \\\\\\ S=180(6)\implies S=1080](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsum%20of%20all%20interior%20angles%20in%20a%20polygon%7D%5C%5C%5C%5C%20S%3D180%28n-2%29~~%20%5Cbegin%7Bcases%7D%20n%3D%5Ctextit%7Bnumber%20of%20sides%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20n%3D8%20%5Cend%7Bcases%7D%5Cimplies%20S%3D180%288-2%29%20%5C%5C%5C%5C%5C%5C%20S%3D180%286%29%5Cimplies%20S%3D1080)
now, we know 7 of those angles are already 835°, so the last one must be 1080 - 835 = 245°.
"a "and "b^2-4ac" must be negetive
Step-by-step explanation:
you do know that 1 cm = 10 mm, right ?
so,
6 cm = 6×1 cm = 6×10 mm = 60 mm
and that is the ultra-ultra long form of doing this ...
Answer:
What statements? Just a sentence from this?
Step-by-step explanation:
Answer:
9x + 7
Step-by-step explanation:
Given
6x + 5y + 3x + 7 - 5y ← collect like terms
= (6x + 3x ) + (5y - 5y ) + 7
= 9x + 0 + 7
= 9x + 7