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2 years ago

JOINNN MY ZO OMMM 95478199526 12345

Mathematics

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luda_lava [24]2 years ago

6 0

Answer:

sorry I can't join your zoom

Svet_ta [14]2 years ago

5 0

Answer:

Step-by-step explanation:

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How to solve -4{1-2x}-1=7x

mina [271]

Answer:

Step-by-step explanation:

$-4(1-2x)-1=7x\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-4)(1)+(-4)(-2x)-1=7x\\\\-4+8x-1=7x\qquad\text{combine like terms}\\\\8x+(-4-1)=7x\\\\8x-5=7x\qquad\text{add 5 to both sides}\\\\8x-5+5=7x+5\\\\8x=7x+5\qquad\text{subtract}\ 7x\ \text{from both sides}\\\\8x-7x=7x-7x+5\\\\x=5$

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2 years ago

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I need help. Plz! ???

Troyanec [42]

Answer: No

Step-by-step explanation: No, because a proportional relationship is a line that goes up at a constant rate, and goes through the origin, an example of a proportional relationship is a straight line starting from the origin ( or what we call the starting point)

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1 year ago

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Marianne collects coffee mugs from places she visits when she goes on vacation. She displays her 87 coffee mugs over her cabinet

lozanna [386]

So the probability of it being California a

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3 years ago

Explain why you cannot square each side of the equation when verifying a trigonometric identity.

Sergeu [11.5K]

This is because when we do verification of an identity, we must work separately on both sides, and to see in the end if we can get an equality. Because if we square both sides, that already means that we assume that the equality exist in the beginning, so no need to verify the identity.

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3 years ago

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Use the Counting Principle to find the probability. Choosing the 7 winning lottery numbers when the numbers are chosen at random

frozen [14]

Answer: 120

<u>Step-by-step explanation:</u>

Since the order of the numbers doesn't matter we can use the formula:

$\dfrac{n!}{r!(n-r)!}\quad \text{where n is the quantity of items and r is the quantity chosen}\\\\\text{In this problem, there are 10 numbers (n = 10) and 7 to be chosen (r = 7)}\\\\_{10}C_{7}=\dfrac{10!}{7!(10-7)!}\\\\.\qquad=\dfrac{10!}{7!3!}\\\\.\qquad=\dfrac{10\times 9\times 8\times 7!}{7!\times 3\times 2\times 1}\\\\.\qquad=10\times 3\times 4\\\\.\qquad=120$

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2 years ago

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