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Sphinxa [80]
4 years ago
15

Twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary a

rrangement. Show that some three consecutive players have the sum of their numbers at least 20.
Mathematics
1 answer:
Ksju [112]4 years ago
6 0

Answer:

Shown

Step-by-step explanation:

Given that twelve basketball players, whose uniforms are numbered 1 through 12, stand around the center ring on the court in an arbitrary arrangement.

Let us consider consecutive numbers in this set.

1+2+3 =6

After this we find the totals are more than 20.

When 1 to 12 are arbitrarily arranged, there are chances that numbers from 6 and above are having consecutive numbers.

These totals are greater than 20

Hence shown that some three consecutive players have the sum of their numbers at least 20.

(i.e. starting from if we take)

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5 times a number increased by 2 is the same as 8 more than 3 times the number. Find the number
wariber [46]

Answer:

5 times a number increased by 2 is the same as 8 more than 3 times the number.

Step-by-step explanation:

8 0
3 years ago
Chester has less than $25 to spend at the county fair. The entrance fee is $5, and each ride costs $3. The number of rides, r, t
Dvinal [7]
C or D hope this helps
5 0
4 years ago
Read 2 more answers
The focal lengths of the objective lens and the eyepiece of a microscope are 0.50 cm and 2.0 cm, respectively, and their separat
VladimirAG [237]

Answer:

- 103.7

Step-by-step explanation:

Given:

Focal length of the eyepiece, f = 2.0 cm

Focal length of the objective lens, f' = 0.50 cm

Separation for minimum eyestrain = 6,0 cm

Image distance, v = - 25 cm

Now, from the lens formula,

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

here, u is the object distance

on substituting the respective values, we get

\frac{1}{2}=\frac{1}{u}+\frac{1}{-25}

or

u = 1.852 cm

also, the separation is adjusted for minimum eyestrain,

therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm

Now, for the objective lens

using the lens formula, we get

\frac{1}{0.5}=\frac{1}{u'}+\frac{1}{4.418}

Here, u' is the distance between the physical object and objective lens

or

u' = 0.568 cm

Thus,

Magnification, m = -\frac{vv'}{ff'}

or

m =-\frac{25\times4.418}{0.5\times2}

or

m = - 103.7

4 0
3 years ago
HELP! 15 POINTS!
Brut [27]

It's pretty easy to go through the choices and none has a[2]=-36 and a[5]=2304.  Something's probably wrong with the way the question is typed, but I will answer what's written.

a_n = a + (n-1) d

a_2 = -36 = a + d

a_5 = 2304 = a + 4d

Subtracting,

2340 = 3d

d = 2340/3 = 780

a = -36 - d = -36 - 780 = -816

Answer: a[n] = -816 + 780(n-1)  which is none of the above

Check:

a_2 = -816 + 780= -36 \quad\checkmark

a_5 = -816 + 780(4) = 2304 \quad\checkmark


8 0
3 years ago
Which table represents a linear function?
Margarita [4]
For this case, what you should know is that a linear function has a constant average rate of change, because its slope is constant.
 Table number two from left to right represents a linear function.
 The line is:
 y-yo = m (x-xo)
 Where
 The slope is:
 m = (0 - (- 5)) / (2-1)
 m = 5/1
 m = 5
 The line is:
 y-0 = 5 (x-2)
 Rewriting:
 y = 5x-10
 Answer:
 
Table two from left to right.
 
The equation is:
 y = 5x-10
6 0
4 years ago
Read 2 more answers
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