The distance between the campsite and the rest area is 9 miles.
The given parameters:
- <em>Initial speed of the campers, u = 4.5 mph</em>
- <em>Final speed of the campers, v = 4 mph</em>
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Let the time of motion from the campsite to rest area = t (hours)
Time for return trip = t hours + 15 mins
= (t + 0.25) hours
Let the distance between the campsite and rest area = d
d = 4.5t
d = 4(t + 0.25)
4.5t = 4(t + 0.25)
4.5t = 4t + 1
4.5t - 4t = 1
0.5t = 1
t = 2 hours
The distance between the campsite and the rest area is calculated as follows;
d = 4.5t
d = 4.5 x 2
d = 9 miles
Thus, the distance between the campsite and the rest area is 9 miles.
Learn more about distance and speed here: brainly.com/question/2854969
If you get 1 and you add that to 9, you will get the sum of 10
B. 60°
∠A = 80°
∠B = ∠A/2 = 80°/2 = 40°
∠C = ?
Sum of all interior angles in a triangle = 180°
180° - 80° - 40° = 60°
∴ the measure of ∠C is 60°.
Answer:B. Health, Safety, and Environmental Management
Explanation:
