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Dvinal [7]
3 years ago
7

1 pt Question 1 If the price of a good increases and consumers purchase more of a related good, the good is a [Select] good?

SAT
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

A complemtary is the answer

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Which of the following statements about global advertising is most correct
shutvik [7]

The statement about global advertising that is most correct is:

C) Global advertising involves developing a single promotional strategy that can be implemented worldwide.

<h3>What is Global Advertising?</h3>

Global advertising is a way of raising awareness for a product in many parts of the world.

In this case, the promotional strategy could be online advertising, direct selling, or even public relations. The aim is for the news to reach the world with any of the strategies.

Complete Question:

Which of the following statements about global advertising is most correct?

A)Firms should avoid advertising in foreign markets and rely instead on otherelements of their promotion mix, such as personal selling and public relations.

B)Television is the best advertising medium for U.S. firms trying to promote theirproducts in foreign countries.

C)Global advertising involves developing a single promotional strategy that canbe implemented worldwide.

D)Given the lower incomes of consumers in many foreign countries, the bestway to promote American goods is utilizing a low price strategy.

Learn more about global advertising here:

brainly.com/question/25556823

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4 0
3 years ago
Lammps ERROR on proc 0: Out of range atoms - cannot compute PPPM
Alexeev081 [22]

Using the knowledge in computational language in C++ it is possible to write a code that Out of range atoms:

<h3>Writting the code in C++:</h3>

<em>#include <cmath></em>

<em>#include "pppm_tip4p.h"</em>

<em>#include "atom.h"</em>

<em>#include "domain.h"</em>

<em>#include "force.h"</em>

<em>#include "memory.h"</em>

<em>#include "error.h"</em>

<em>#include "math_const.h"</em>

<em />

<em>using namespace LAMMPS_NS;</em>

<em>using namespace MathConst;</em>

<em />

<em>#define OFFSET 16384</em>

<em />

<em>#ifdef FFT_SINGLE</em>

<em>#define ZEROF 0.0f</em>

<em>#define ONEF  1.0f</em>

<em>#else</em>

<em>#define ZEROF 0.0</em>

<em>#define ONEF  1.0</em>

<em>#endif</em>

<em />

<em>void PPPMTIP4P::init()</em>

<em>{</em>

<em>  // TIP4P PPPM requires newton on, b/c it computes forces on ghost atoms</em>

<em />

<em>  if (force->newton == 0)</em>

<em>    error->all(FLERR,"Kspace style pppm/tip4p requires newton on");</em>

<em />

<em>  PPPM::init();</em>

<em>}</em>

<em />

<em>void PPPMTIP4P::particle_map()</em>

<em>{</em>

<em>  int nx,ny,nz,iH1,iH2;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  if (!std::isfinite(boxlo[0]) || !std::isfinite(boxlo[1]) || !std::isfinite(boxlo[2]))</em>

<em>    error->one(FLERR,"Non-numeric box dimensions - simulation unstable");</em>

<em />

<em>  int flag = 0;</em>

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = static_cast<int> ((xi[0]-boxlo[0])*delxinv+shift) - OFFSET;</em>

<em>    ny = static_cast<int> ((xi[1]-boxlo[1])*delyinv+shift) - OFFSET;</em>

<em>    nz = static_cast<int> ((xi[2]-boxlo[2])*delzinv+shift) - OFFSET;</em>

<em />

<em>    part2grid[i][0] = nx;</em>

<em>    part2grid[i][1] = ny;</em>

<em>    part2grid[i][2] = nz;</em>

<em />

<em>    if (nx+nlower < nxlo_out || nx+nupper > nxhi_out ||</em>

<em>        ny+nlower < nylo_out || ny+nupper > nyhi_out ||</em>

<em>        nz+nlower < nzlo_out || nz+nupper > nzhi_out) flag++;</em>

<em>  }</em>

<em />

<em>  int flag_all;</em>

<em>  MPI_Allreduce(&flag,&flag_all,1,MPI_INT,MPI_SUM,world);</em>

<em>  if (flag_all) error->all(FLERR,"Out of range atoms - cannot compute PPPM");</em>

<em>}</em>

<em>void PPPMTIP4P::make_rho()</em>

<em>{</em>

<em>  int i,l,m,n,nx,ny,nz,mx,my,mz,iH1,iH2;</em>

<em>  FFT_SCALAR dx,dy,dz,x0,y0,z0;</em>

<em>  double *xi,xM[3];</em>

<em />

<em>  FFT_SCALAR *vec = &density_brick[nzlo_out][nylo_out][nxlo_out];</em>

<em>  for (i = 0; i < ngrid; i++) vec[i] = ZEROF;</em>

<em />

<em>  int *type = atom->type;</em>

<em>  double *q = atom->q;</em>

<em>  double **x = atom->x;</em>

<em>  int nlocal = atom->nlocal;</em>

<em />

<em>  for (int i = 0; i < nlocal; i++) {</em>

<em>    if (type[i] == typeO) {</em>

<em>      find_M(i,iH1,iH2,xM);</em>

<em>      xi = xM;</em>

<em>    } else xi = x[i];</em>

<em />

<em>    nx = part2grid[i][0];</em>

<em>    ny = part2grid[i][1];</em>

<em>    nz = part2grid[i][2];</em>

<em>    dx = nx+shiftone - (xi[0]-boxlo[0])*delxinv;</em>

<em>    dy = ny+shiftone - (xi[1]-boxlo[1])*delyinv;</em>

<em>    dz = nz+shiftone - (xi[2]-boxlo[2])*delzinv;</em>

<em />

<em>    compute_rho1d(dx,dy,dz);</em>

<em />

<em>    z0 = delvolinv * q[i];</em>

<em>    for (n = nlower; n <= nupper; n++) {</em>

<em>      mz = n+nz;</em>

<em>      y0 = z0*rho1d[2][n];</em>

<em>      for (m = nlower; m <= nupper; m++) {</em>

<em>        my = m+ny;</em>

<em>        x0 = y0*rho1d[1][m];</em>

<em>        for (l = nlower; l <= nupper; l++) {</em>

<em>          mx = l+nx;</em>

<em>          density_brick[mz][my][mx] += x0*rho1d[0][l];</em>

<em>        }</em>

<em>      }</em>

<em>    }</em>

<em>  }</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

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6 0
2 years ago
Your working with an experienced associate walmart.
kondaur [170]

Answer:

should be You're working with an experienced associate AT Walmart.

Explanation:

4 0
2 years ago
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Por que estoy loca por este anime?​
Sunny_sXe [5.5K]

Hola aquí va la respuesta!!

Cuando una pacífica manifestación de estudio del reclamo de medidas concretas para la defensa del Chaco fue justamente reprimida a bulacos

5 0
3 years ago
The lengths of two sides of an isosceles triangle are eight and 10. what is the length of the third side
leva [86]

The length of the third side can be either 10 or 8, if the lengths of two sides of an isosceles triangle are eight and 10.

According to the given question.

The lengths of two sides of an isosceles triangle are 8 and 10.

Since, the properties of an isosceles triangle are

  • Two sides are congruent to each other.
  • The sum of the length of the two sides of a triangle is greater than the length of the third side.
  • The difference between the two sides of a triangle is less than the length of the third side.

So, according to the property of an isosceles triangle

The third side must be less than the sum of 8 and 10.

⇒ length of third side < 8 + 10

⇒ length of third side < 18

And,

Length of the third side > 10 - 8

⇒ length of the third side > 2

But, the triangle is an isosceles triangle therefore, the third side must be either 8 or 10.

And

8 or 10 both are less than 18 and greater than 2.

Therefore, the length of the third side can be either 10 or 8.

Find out more information about isosceles triangle here:

brainly.com/question/12358458

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3 0
2 years ago
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