Answer:
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Step-by-step explanation:
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Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y

Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:





Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is 
Answer:
2x(x2-2x-15)
2x(x-5).(x+3)=0
x=0
x=5
x=-3
Step-by-step explanation:
Answer:
m∠CPD = 129.75°
Step-by-step explanation:
m∠APD + m∠APB = 180 since the angles are supplementary
x + 1 + 3x - 18 = 180
4x - 17 = 180
4x = 197
x = 49.25
m∠APB = 3(49.25) - 18 = 129.75
m∠APB = m∠CPD because the angles are vertical angles
m∠CPD = 129.75°
X=74/26
x=37/13
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