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tatiyna
2 years ago
5

Use the 3 trig ratios to find each unknown side length. Round all answers to 1 decimal

Mathematics
1 answer:
katrin [286]2 years ago
8 0

<em>Note: As you missed to add the graph of mentioning the complete question.</em>

<em>So, I am solving your concept based on an assumed graph which I have attached. It would anyways clear your concept.</em>

<em></em>

Answer:

Please check the explanation!

Step-by-step explanation:

Given the attached graph below, it is clear that the right angle triangle ABC is shown.

Here are some of the information we can get from the right angle triangle ABC such as:

  • The angle at C = 30°
  • side AB = 8 units

We have to determine the unknown side 'x' using the trigonometric ratios

As

tan Ф = opp/adjacent

From the diagram it is clear that

Ф = 30°

opp=8

adjacent = BC = x

so

tan Ф = opp/adjacent

tan 30 = 8/x

1/√3 = 8/x

x = 8×√3

x = 13.9

Therefore, the missing length will be: x = 13.9

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yawa3891 [41]

Step-by-step explanation:

The system of linear equations are , (i) y = 2x and (ii) y = x + 1 . We will find some coordinates and then we will plot its graph. The point where both Graphs will meet will be the solution of the graph .

<u>•</u><u> </u><u>Findin</u><u>g</u><u> </u><u>coordinates</u><u> </u><u>of </u><u>Equ</u><u>ⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>:</u><u>-</u>

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\tt y = 2x = 2(0) = \red{0}

Step 2: <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\tt y = 2x = 2(1) = \red{2}

\boxed{\begin{array}{c|c|c} \bf x & \tt 0 &\tt 1 \\ \bf y &\tt 0 & \tt 2 \end{array}}

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>•</u><u> </u><u>Finding</u><u> </u><u>coord</u><u>inates</u><u> </u><u>of</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>:</u><u>-</u>

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Now plot these points on the graph Taking appropriate scale . Refer to the attachment in graph . From graph the Solution is (1,2) .

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