Answer:
Chandra Gupta I, King of India reigned from 320 to about 330 CE and founder of the Gupta empire. He was the grandson of Sri Gupta, the first known leader of the Gupta line. Chandra Gupta I, whose first life is unknown, became the local chief of the kingdom of Magadha parts of the modern state of Bihar.
Step-by-step explanation:
Answer:
286 in³
Step-by-step explanation:
7×5 = 35
35×2 = 70in
9×5 = 45
45×2 = 90in
9×7 = 63
63×2 = 126in
70+90+126
=286in³
Answer:
-3.6
Step-by-step explanation:
Simplifying
7 + 3x + 4 = 0
Reorder the terms:
7 + 4 + 3x = 0
Combine like terms: 7 + 4 = 11
11 + 3x = 0
Solving
11 + 3x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-11' to each side of the equation.
11 + -11 + 3x = 0 + -11
Combine like terms: 11 + -11 = 0
0 + 3x = 0 + -11
3x = 0 + -11
Combine like terms: 0 + -11 = -11
3x = -11
Divide each side by '3'.
x = -3.666666667
Simplifying
x = -3.666666667
Answer:
Equation of the tangent to the curve
y = 240x - 215994
Equation of the normal
y = (-1/240)x + 9.75 = - 0.00417x + 9.75
Step-by-step explanation:
y = (6 + 4x)² = 36 + 48x + 16x² = 16x² + 48x + 36
dy/dx = 32x + 48
At the point (6,900),
dy/dx = 32(6) + 48 = 240
Equation of the tangent at point (a,b) is
(y - b) = m(x - a)
a = 6, b = 900, m = 240
y - 6 = 240(x - 900)
In the y = mx + b form,
y - 6 = 240x - 216000
y = 240x - 215994
The slope of the normal line = -(1/slope of the tangent line) (since they're both perpenducular to each other)
Slope of the normal line = -1/240
Equation of normal
y - 6 = (-1/240)(x - 900)
y - 6 = (-x/240) + 3.75
y = (-1/240)x + 9.75
y = - 0.00417x + 9.75
Answer:
B) 12.6π ; 39.6
Step-by-step explanation:
Circumference:
C = 2πr
C = 2(3.14)(6.3)
C = 6.28(6.3)
C = 39.6
C = 2πr
C = 2π6.3
C = 12.6π
