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Rudiy27
3 years ago
9

Write an expression that has three terms, two different variables, and one constant

Mathematics
1 answer:
morpeh [17]3 years ago
7 0

This should do it:        2x + 3y + 4
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Please help me with this
FrozenT [24]
See you Need to round it so it is c=-4
5 0
3 years ago
Determine the quadrant(s) in which (x,y) is located so that the condition is satisfied. (Select all that apply.)
Svetllana [295]
I’m not exactly sure but I think II and IV.
4 0
3 years ago
Please Help!!!
mylen [45]
B and C are absurd; if a series converges, it must have a sum, but if a series diverges, it cannot have a sum.

Now, notice that

\dfrac12+\dfrac29+\dfrac4{27}+\dfrac8{81}+\cdots=\dfrac12+\dfrac{2^{2-1}}{3^2}+\dfrac{2^{3-1}}{3^3}+\dfrac{2^{4-1}}{3^4}+\cdots

That is, we can write the sum more compactly as

\dfrac12+\dfrac12\displaystyle\sum_{n=1}^\infty\left(\frac23\right)^n

The series is geometric with common ratio \dfrac23, so the series converges (and thereby has a sum), so the answer is D.
6 0
3 years ago
2y/5y cube + 4y square + 6y
timama [110]

Answer:

here down is the answer

(2y/5y)^3+4y^2+6y

8y^3/125y^3 +16y^2+6y

8/125+16y^2+6y

8/125+16y^2+6y=0

16y^2+6y+8/125=0

it is in the form of quadratic equation

formula :

x=(-b+-square root of b^2-4ac) /2a

here a=16,b=6&c=8/125

x=(-b+-square root of b^2-4ac)/2a

x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation

x=(-6+-31.91)/2

so

x=(-6+31.91)/2 first (+);

x=25.91/2

x=12.955;

x=(-6-31.91)/2 then(-);

x=-37.91/2

x=-18.955 ;

ans is = 12.955&-18.955;

6 0
3 years ago
Help please this is geometry!!!
Arada [10]

Answer:

i really dont know and do you know how i really dont know

Step-by-step explanation:

it bc i dont literally

3 0
3 years ago
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