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Yuliya22 [10]
3 years ago
7

A bicycle that normally sells for $180 is on sale for 40% off. What is the

Mathematics
1 answer:
Kitty [74]3 years ago
5 0

Answer:

$108 i think

Step-by-step explanation:

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Help find slope of each line
gizmo_the_mogwai [7]
Slope=-5

as the line goes 5 down and 1 right
3 0
3 years ago
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Can someone explain this for me??<br> 4 (c+2) &lt; 4c + 10
faust18 [17]

Answer:

The inequality would be true

Step-by-step explanation:

4(c+2) < 4c + 10

Distribute the 4 on the left

4c + 8 < 4c + 10

Subtract 4c from both sides

8 < 10

8 < 10 is true

7 0
3 years ago
What is the graph of the function f(x) = -x^2+x+20/x+4
mr_godi [17]
F(x) = (-x²+x+20) / (x+4)

-x²+x+20     | x+4
+x²+4x          -x+5
 \\\\ 5x+20
     -5x-20
      \\\\\\\\\
 
 f(x) = (x+4)(-x+5) / (x+4)
 
 f(x) = (-x+5)

The graph is a decreasing line, with origin from 5.



   

3 0
3 years ago
Can someone pls graph the picture below.
grin007 [14]

Answer:

  see below

Step-by-step explanation:

This graphs as 3 horizontal lines. The open circles are at the ends of the interval where the function is undefined or is defined as a different value.

3 0
3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
4 years ago
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