Step-by-step explanation:
bruh did u have hentoi as your pic
Find the marginal density for 
by integrating the joint PDF over all possible values of 
:
Then the density of 
conditioned on is
for 
and undefined elsewhere.
Thus
= = =
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Answer:
b) the coefficient of x of jamie's polynomial is 5 .
c) The two polynomials are :
x³ + 4x² + 5x + 4
x³ - 2x² + 5x + 4
Step-by-step explanation:
consider these two Monic polynomials of degree 3:
P : x³ + ax² + bx² + c
Q : x³ + a₁x² + bx² + c
P × Q = x⁶+ (a+a₁)x⁵ + (aa₁+2b)x⁴ + (ab+a₁b+2c)x³ + (ac+a₁c+b²)x² +2bcx + c²
Now we compare the coefficients of P × Q and x⁶ + 2x⁵ +2x⁴ + 18x³ + 33x² + 40x + 16
b)
c² = 16 ⇒ c = 4 (c is positive)
2bc = 40 ⇒ 8b = 40 ⇒ b = 5 then the coefficient of x of jamie's polynomial is 5 .
c)
In order to find a and a₁ we need to solve this system:
a+a₁ = 2 a+a₁ = 2
⇔
aa₁+2b = 2 aa₁ = -8
Solve the system and you’ll get :
a = 4 and a₁ = -2 or a = -2 and a₁ = 4
Let’s choose a = 4 and a₁ = -2 then
the two polynomials are respectively:
P : x³ + ax² + bx² + c = x³ + 4x² + 5x + 4
Q : x³ + a₁x² + bx² + c = x³ - 2x² + 5x + 4
Answer:
x = -1
Step-by-step explanation:
1) First, find the slope of the line by using the slope formula, 
. Substitute the x and y values of the given points into the formula and solve:
The result we got was 
, but we can't divide by zero. This means that the slope of the line must be undefined instead.
2) All vertical lines have a slope that is undefined. So, this line must be vertical.
All vertical lines are represented by the equation x = a single number. That number represents the x-value of all the points the vertical line intersects. So, take the x-value of the given points (in this case, -1) and put it into that equation. So, the equation of the line must be x = -1.
Answer:
4
Step-by-step explanation:
