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S_A_V [24]
3 years ago
5

Problem 1 a jar contains blue, red and green balls. the null-hypothesis h0 is that there is 25% percent of red balls. (1) a samp

le of 36 ball have been randomly pull out of jar. it contained 16 red balls. what is the probability of that happening? do you still believe that jar contains 25% red balls? answer:_____________________________________________________ (2) we create a statistic which we will use to test the h0 . the statistic is simply a number of red balls in the sample of 36 balls. we make a decision that we will reject the null-hypothesis if sample contains more than 15 red balls. what is the probability of that happening assuming that null-hypothesis is true?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0
(1) the probability of that happening is .4444.. so on. the jar isnt 25% red balls because 25% of 36 is only 9 and he pulled out 16 red balls. 

I dont know number two sorry.
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Reasoning A store sells packages of comic books with a poster. A poster and 5 comics cost ​$13.99. A poster and 12 comics cost ​
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Answer:

Step-by-step explanation:

Reasoning A store sells packages of comic books with a poster. A poster and 5 comics cost ​$13.99. A poster and 12 comics cost ​$20.99. Write a linear function rule that models the cost y of a package containing any number x of comic books. Suppose another store sells a similar​ package, modeled by a linear function rule with initial value ​$. Use pencil and paper. Explain which store has the better deal. The linear function rule is y nothing.

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Which exspression is equivalent to :
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Item 16 a dentist's office and parking lot are on a rectangular piece of land. the area (in square meters) of the land is repres
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3 years ago
Word problem.. i need help. Due at midnight
aniked [119]

The Brady family received 1 letter on July 28.

Step-by-step explanation:

Step 1:

Assume a = the number of letters, b = the number of bills, c = the number of ads, and d = the number of magazines.

From the question, they got 15 pieces of mail that day so a+b+c+d=15.

They got 5 more magazines than bills so d = b + 5.

The got the same number of letters as ads so a=c.

They got 3 more bills than ads so b= c + 3.

Step 2:

As we have only one equation to solve the values, we need to make every term in terms of a single term.

We make everything in terms of c.

So a=c, b = c+3, c=c, d = b+5 = (c+3)+5=c+8.

Substituting all this in the equation, we get

a + b+c+d =(c)+(c+3)+(c)+(c+8) = 15, 4c+11=15.

4c=4, c = 1.

Step 3:

Substituting c = 1 in other terms, we get

a=c=1,

b=c+3=1+3=4,

c=1, and

d = c+8 = 1+8=9.

As a = 1, they received 1 letter that day.

8 0
3 years ago
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