Each van carries 13 students and each bus carries 25 students.
<h3><u>Distribution</u></h3>
Given that the senior class at High School A and the senior class at High School B both planned trips to Yellowstone, and the senior class at High School A rented and filled 5 vans and 2 buses with 115 students, while High School B rented and filled 1 van and 6 buses with 163 students, and each van carried the same number of students and each bus carried the same number of students, to determine the number of students in each van and in each bus, the following calculation must be made:
- 5X + 2Y = 115
- 1X + 6Y = 163
- 5X + 2Y = 115
- 5X + 30Y = 815
- 815 - 115 = 28Y
- 700 = 28Y
- Y = 700 / 28
- y = 25
- 1X + 6x25 = 163
- 1X = 163 - 150
- X = 13
Therefore, each van carries 13 students and each bus carries 25 students.
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Answer: A
Step-by-step explanation:
The ratio is simply 2:5
You are comparing the two times
2 3/8 - 1/4 = 2 1/8 x 1/8 = 17/64.
To do this, you first need to do the problem in the (). You have to turn 1/4 with a denominator of eight, so the fraction becomes 2/8. 2 3/8 - 2/8 = 2 1/8. Now we have to turn 2 1/8 into an improper fraction by doing whole number x denominator + numerator. 17/8 x 1/8 = 17/64.
Percent error is calculated using
((Actual - predicted) / actual) * 100
In this case, the actual value of the number of pages he read is 20. The expected value was 23. So simply plug in:
((20 - 23) / 20) * 100 = -15%
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Answer:
The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).
