10g^3 - 8g^2 + 5g - 14 + 10g^2 + 12g
its just a matter of combining like terms
10g^3 + 2g^2 + 17g - 14
The answer is the 3rd one
There would be 1 real zero and two complex zeros
Notice the following pattern:
2 - 0 = 2
6 - 2 = 4
12 - 6 = 6
20 - 12 = 8
It's reasonable to assume that consecutive terms in the sequence differ by increasing multiples of 2, so that for the next number (call it x) we expect to see
x - 20 = 10 ==> x = 30
and for the number after that (call it y) we would see
y - x = y - 30 = 12 ==> y = 42
