Ok first we can split it in two :

and

.
The derivative of

is 3.
For the first part, we use the chain rule :
![[f(g(x))]'=g'(x)f'(g(x))](https://tex.z-dn.net/?f=%5Bf%28g%28x%29%29%5D%27%3Dg%27%28x%29f%27%28g%28x%29%29)
hence

(since the derivative of the exponential is itself) hence
Answer:

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Step-by-step explanation:
Let the number be x.

Dividing both sides by 4,

Subtracting 8 from both sides,

The number is -7.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
He passed out 91 objects. 13 x 4 = 52 + 39 = 3 x 13
Here’s the answer, hope it helps. Btw these are screenshots from someone else’s work not mine