Answer:2.50
Step-by-step explanation:
Answer:
± 
, 
Step-by-step explanation:
See the attached image
This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are:
that correspond to the force of resistance on the mass by the action of the spring and
that is an external force with unknown direction (that does not specify in the enounce).
For determinate
we can use Hooke's Law given by the formula
where
correspond to the elastic constant of the spring and
correspond to the relative displacement of the mass-spring system with respect of his rest state.
We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

Now we apply Newton's 2nd Law and obtaint that...
±
= 




Finally...
± 
We know from the problem that there's not initial displacement and initial velocity, so...
and 
Finally the Initial Value Problem that models the situation describe by the problem is

Answer:
5m-7
Step-by-step explanation:
you only combine the common numbers
The answer to this is y=-1/2*-3+2
Answer:
The correct answer is A, 14%.
Step-by-step explanation:
All you have to do is take the 30% chance of you HAVING to stop at the first light and find the chance that you won't have to stop at the first light, which is 70%, or .7. Then you take the chance of having to stop at the second light which is 80%, and find the probability of NOT having to stop there, which is 20%, or .2. Then you multiply the probabilities of not having to stop, which equals .14.