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tankabanditka [31]
3 years ago
5

Hi i’ll give brainliest but you gotta give a correct answer thanks

Mathematics
2 answers:
AfilCa [17]3 years ago
5 0

social programs

social programs

Reptile [31]3 years ago
4 0

Answer:

social programs

hope it is helpful to you

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10y-50=<br> 10y−50=<br> \,\,-20<br> −20
densk [106]

Answer:

Therefore the value of 'y' is,

y=3

Step-by-step explanation:

Given:

10y-50=-20

To Find:

y= ?

Solution:

10y-50=-20    ........Given

Step 1. Adding 50 to both the side we get

10y-50+50=-20+50\\10y=30

Step 2. Dividing by 10 on both the side we get

\dfrac{10y}{10}=\dfrac{30}{10}\\\\y=3

Therefore the value of 'y' is,

y=3

6 0
3 years ago
NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE
tia_tia [17]

Answer:

Q1:

-5\sqrt{27c^2}

-5\sqrt{27}\sqrt{c^2}

-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}

-5\times3\sqrt{3}\sqrt{c^2}

-5\times3\sqrt{3}c

-15\sqrt{3}c

Q2:

5\sqrt{72}-3\sqrt{32}

5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}

5\times6\sqrt{2}-3\times4\sqrt{2}

30\sqrt{2}-12\sqrt{2}

18\sqrt{2}

Q3:

\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}

\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}

6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}

16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}

Q4:

\sqrt{15n^2}\sqrt{10n^3}

\sqrt{15}n\sqrt{10n^3}

\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}

\sqrt{15}\sqrt{10}n^2\sqrt{n}

\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}

5\sqrt{3}\sqrt{2}n^2\sqrt{n}

5\sqrt{6}n^2\sqrt{n}

Q5:

\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}

\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}

Cancel off \sqrt{x}:

\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}

Cancel off y:

\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}

Cancel off \sqrt{y} :

\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}

Multiply \sqrt{5} on the numerator and denominator:

\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}

\frac{\sqrt{15}\sqrt{x}}{20}

5 0
3 years ago
What is the horizontal asymptote of the function f(x)= -2x/x+1
daser333 [38]

<u>Answer:</u>

-2

<u>Step-by-step explanation:</u>

We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.

Recalling the rules for a horizontal asymptote:

1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.

2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.

Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.

Horizontal asymptote = -\frac{2}{1} = -2

8 0
3 years ago
Y = x2+6x+8 and y = (x+2)(x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of th
mash [69]

Answer:

x-int:(-2,0)(-4,0) . y-int:(0,8)

Step-by-step explanation:

y = x2+6x+8 and y = (x+2)(x+4)

x-int:

x+2=0

x= -2

(-2,0)

x-int:

x+4=0

x=-4

(-4,0)

y-int: plug 0 for x

y=(0+2)(0+4)

y=8

(0,8)

3 0
3 years ago
Which is less: (-20)+10 or 20+(-35)? Explain your answer.
hjlf

Answer:

20 + (-35)

Step-by-step explanation:

(-20) + 10 = -10

20 + (-35) = -15

8 0
3 years ago
Read 2 more answers
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