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BartSMP [9]
3 years ago
11

Y = x2+6x+8 and y = (x+2)(x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of th

e graph.
Put each of the intercepts in the form of an ordered pair ( . ) ( . ).

You should have three ordered pairs in your answer. Two x-intercepts and one y-intercept. ​
Mathematics
1 answer:
mash [69]3 years ago
3 0

Answer:

x-int:(-2,0)(-4,0) . y-int:(0,8)

Step-by-step explanation:

y = x2+6x+8 and y = (x+2)(x+4)

x-int:

x+2=0

x= -2

(-2,0)

x-int:

x+4=0

x=-4

(-4,0)

y-int: plug 0 for x

y=(0+2)(0+4)

y=8

(0,8)

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4 years ago
Solve the equation for θ, where
elena-s [515]

Answer:

\dfrac{\pi}{4},\dfrac{3\pi}{4}

Step-by-step explanation:

2\sin^2(\theta)=1

Divide both sides by 2:

\sin^2(\theta)=\dfrac{1}{2}

Take the square root of both sides:

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Hope this helps!

4 0
4 years ago
What kinds of functions can be integrated using partial fraction decomposition? Choose the correct answer below
zaharov [31]

Answer:

B. Rational functions

Step-by-step explanation:

The partial fraction decomposition is used for functions there are described by fractions, and for which the substitution method is not possible. These are rational functions, in which both the numerator and the denominator are polynomials.

So the correct answer is:

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4 0
3 years ago
$2000 was borrowed for 4 years with an interest rate of 3% compounded annually. What is the total amount owed at the end of the
kompoz [17]

Answer:

\$2,251.02  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the total amount owed  

P is the amount of money borrowed

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=4\ years\\ P=\$2,000\\ r=3\%=3/100=0.03\\n=1  

substitute in the formula above  

A=2,000*(1+\frac{0.03}{1})^{1*4}  

A=2,000*(1.03)^{4}  

A=\$2,251.02  

4 0
3 years ago
Read 2 more answers
What is 975310 in words
sweet-ann [11.9K]

"Nine hundred seventy-five thousand, three hundred ten"
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