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Leno4ka [110]
3 years ago
9

What is the value of x? x 360 22°

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

x just represents a number

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What is the answer
vichka [17]
An excluded value is one where the bottom of the fraction = 0.

In your case 1-3x=0
1=3x
x=1/3

At this point, the function does not exist. If you were to draw a graph of it, there wouldn't be a y-value corresponding to x=1/3.
4 0
3 years ago
What is the area, in square inches, of the isosceles trapezoid below?
zimovet [89]

Answer:

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

=> 9.6 / 2

=> 4.8

So, Height of the Triangle = 8

      Base of the triangle = 4.8

Area of a rectangle

=> 8.3 x 8

=> 66.4

Area of the triangle

=> 1/2 x 8 x 4.8

=> 4 x 4.8

=> 19.2

There are 2 triangles:

=> 19.2 x 2

=> 38.4

=> 66.4 + 38.4

=> 104.8

The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

6 0
3 years ago
Solve step by step! Please answer correctly !!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!
Colt1911 [192]

Answer:

X is an acute angle, which means it is less than 90*, so it is probably 45*

Step-by-step explanation:

I was confused at first but then, I’m just like, I can solve this!

3 0
2 years ago
Read 2 more answers
Pre-Test
fiasKO [112]

Answer:

x5

Step-by-step explanation:

5 0
3 years ago
Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours. Then pumps Y and Z started working an
madam [21]

Answer:

The correct option is B) 12.

Step-by-step explanation:

Consider the provided information.

Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours.

As we know: rate =\dfrac{ work}{time},

The rate of pump X is \frac{\frac{1}{4}}{2} = \frac{1}{8}

\frac{1}{4} of the water is pumped out of the tank, that means only \frac{3}{4} is left to be pumped out.  

All 3 pumps pumped out the remaining \frac{3}{4} of the water out in 3 hours.

The combined rate of all three pumps is: \frac{\frac{3}{4}}{3} = \frac{1}{4}

Pump Y, working alone at its constant rate, would have taken 18 hours to pump out the rest of the water.

The rate of pump Y = \frac{\frac{3}{4}}{18} = \frac{1}{24}

Let z is the time taken by pump Z, then the rate of pump Z is \frac{1}{z}.

Therefore,

\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{z}=\dfrac{1}{4}

Multiplying both sides by 24 z.

3z + z + 24 = 6z\\24 = 2z\\12 = z

Hence, the correct option is B) 12.

5 0
3 years ago
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