A binomial squared is written like
![x^2+2ax+a^2](https://tex.z-dn.net/?f=%20x%5E2%2B2ax%2Ba%5E2%20)
So, we have ![2a=6 \iff a=3](https://tex.z-dn.net/?f=2a%3D6%20%5Ciff%20a%3D3%20)
So, we want to complete the square ![(x+3)^2 = x^2+6x+9](https://tex.z-dn.net/?f=%28x%2B3%29%5E2%20%3D%20x%5E2%2B6x%2B9)
We can add and subtract 9 to write
![x^2+6x = x^2+6x+(9-9) = (x^2+6x+9)-9 = (x+3)^2-9](https://tex.z-dn.net/?f=x%5E2%2B6x%20%3D%20x%5E2%2B6x%2B%289-9%29%20%3D%20%28x%5E2%2B6x%2B9%29-9%20%3D%20%28x%2B3%29%5E2-9)
-7.1+-5.8=-12.9
hope this helps :)
Xz+y+1=z. given
y+1=z-xz. subtraction property of equality
y+1=z(1-x) distributive property of multiplication over addition/factoring
(1+y)/(1-x) = z division property of required, given x≠1
Answer:
30 units
Step-by-step explanation:
The formula for finding the area of a triangle is 1/2b x h
So b = 12
and h = 5
1/2(12) = 6
6 x 5 = 30
I could be wrong here so
Here's a little tip:
I can tell you're using G.oogle Forms, so you can press ctrl + U and find the answers in the code