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3 years ago

What is he answer to this I rlly need help

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

7 0

I think the area that is NOT the porch is 716 ft but not sure abt the porch area

Thepotemich [5.8K]3 years ago

3 0

So the right answer is B 942 ft^2

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Find the difference. (9/x^2-9x)-(6/x^2-81)

Sunny_sXe [5.5K]

The difference is $\frac{3 x+81}{x(x-9)(x+9)}$

Explanation:

The expression is $\left(\frac{9}{x^{2}-9 x}\right)-\left(\frac{6}{x^{2}-81}\right)$

Removing the parenthesis, we have,

$\left\frac{9}{x^{2}-9 x}\right-\left\frac{6}{x^{2}-81}\right$

Factoring the terms $x^{2}-9 x$ and $x^{2}-81$ , we get,

$\frac{9}{x(x-9)}-\frac{6}{(x+9)(x-9)}$

Taking LCM, we get,

$\frac{9(x+9)-6x}{x(x-9)(x+9)}}$

Simplifying the numerator, we get,

$\frac{9x+81-6x}{x(x-9)(x+9)}}$

Subtracting the numerator, we have,

$\frac{3 x+81}{x(x-9)(x+9)}$

Hence, the difference is $\frac{3 x+81}{x(x-9)(x+9)}$

7 0

3 years ago

Particle x moves along the positive x-axis so that it's position at time t is less than equal to 0 is given by x(t)= 5t^3 - 9t^2

serg [7]

Answer:

Step-by-step explanation:

Given the position of the particle expressed using the expression;

x(t)= 5t^3 - 9t^2 + 7 where;

x moves along the positive x-axis

when t = 1

x(1) = 5(1)^3 - 9(1)^2 + 7

x(1) = 5 - 9 + 7

x(1) = -4 + 7

x(1) = 3

<em>Since the position of the particle is positive at t = 1, hence the particle is moving towards the right at time t = 1</em>

8 0

3 years ago

Find the distance from point (-1, 3) to the line 5 x - 4 y = 10.

Wewaii [24]

We could use the formula, derive the formula, or just work it out for this case. Let's do the latter.

The distance of a point to a line is the length of the perpendicular from the line to the point.

So we need the perpendicular to 5x-4y=10 through (-1,3). To get the perpendicular family we swap x and y coefficients, negating one. We get the constant straightforwardly from the point we're going through:

4x + 5y = 4(-1)+5(3) = 11

Those lines meet at the foot of the perpendicular, which is what we're after.

4x + 5y = 11

5 x - 4y = 10

We eliminate y by multiplying the first by four, the second by five and adding.

16x + 20y = 44

25x - 20y = 50

41x = 94

x = 94/41

y = (11 - 4x)/5 = 15/41

We want the distance from (-1,3) to (94/41,15/41)

$d = \sqrt{ (-1 - 94/41)^2 + (3 - 15/41)^2 } = \dfrac{27}{\sqrt{41}}$

8 0

4 years ago

What is the solution to the equation?<br> (+55 - 466<br><br> HELLLPP

maksim [4K]

Answer:

Option D

Step-by-step explanation:

466 - 55 =411

411 = t

6 0

4 years ago

Read 2 more answers