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Fed [463]
3 years ago
6

NEED ANSWERS ASAP

Computers and Technology
2 answers:
Law Incorporation [45]3 years ago
5 0
The second option:) said
a_sh-v [17]3 years ago
5 0

Answer:

jeavfdnshbdaubunsd

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What was the name of first computer?
viva [34]
The ENIAC (Electronic Numerical Integrator and Computer) was the first electronic programmable computer built in the U.S. Although the ENIAC was similar to the Colossus, it was much faster, more flexible, and it was Turing-complete.
7 0
3 years ago
Pls help its not school work i just need this fixed
Bingel [31]

Answer:

This just means that you have no file in your computer named 'Requirments' hence it is not able to retrieve any data from there.

6 0
3 years ago
What was the first general purpose, programmable, electronic computer?.
ryzh [129]

Answer:

ENIAC: first general-purpose electronic computer.

Explanation:

6 0
3 years ago
Test prints can help you determine the exposure time for a print as well as help you identify any issues in the negative. True F
Dahasolnce [82]
I'd say TRUE

It is always important to have a correct exposure in rendering a highlight tone on a print. To find the correct highlight exposure, make test strips using pieces of paper separately to the area of the negative containing the most the most critical highlight. Once you have enough test strips, you should pick the one that contains the best highlight rendering. Exposure time of that test strip is the correct exposure.



5 0
4 years ago
Read 2 more answers
Segmentation Faults Recall what causes segmentation fault and bus errors from lecture. Common cause is an invalid pointer or add
vfiekz [6]

Answer:

See Explanation

Explanation:

Q13. Line that caused the segmentation fault?

The segmentation fault was caused by line 15 i.e. scanf("%d",input);

Q14. How the line was fixed?

The reason for the segmentation fault is that the instruction to get input from the user into the integer variable "input" was not done correctly.

The correction to this is to modify scanf("d",input) to scanf("%d",input);

Q15. The bug?

The bug is that the method needs to return two value; the sum of the inputted numbers and the count of the inputted numbers.

However. it only returns the count of the inputted number.

So, the average is calculated as: 0/count, which will always be 0

How it was fixed?

First, change the method definition to: void and also include an array as one of its parameters.

<em>void read_values(double sum, double arr []) {</em>

Next:

<em>assign sum to arr[0] and values to arr[1]</em>

<em />

In the main method:

Declare an array variable: double arr [2];

Call the read_values function using: read_values(sum,arr);

Get the sum and values using:

<em>sum = arr[0];</em>

<em>values = arr[1];</em>

<em />

Lastly, calculate and print average:

<em>printf("Average: %g\n",sum/values);</em>

See attachment for complete modified program

Download txt
8 0
3 years ago
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