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3 years ago

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According to your lecture, what do successful students do? a. Study harder than everyone else c. Learn faster than other student

s b. Study more often than everyone else d. Make studying part of their daily routine Please select the best answer from the choices provided

2 answers:

Inessa05 [86]3 years ago

4 0

Answer:

On EDG the answer is D

Step-by-step explanation:

Maurinko [17]3 years ago

4 0

Answer:

the answer is d

Step-by-step explanation:

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mark ordere wome balloons for a party that she is having.The balloons cost $4.50 each and there is a service fee of $12.The tota

ohaa [14]

A general equation to use for this situation is y = mx + b.

For this question, we can assume that y is total cost, m is cost per balloon, x is the amount of balloons, and b as the service fee; so we can set the equation up:

y = (4.50)x + 12

And we can further plug in the total cost to find the number of balloons purchased for the party:

79.50 = (4.50)x + 12

Now we can solve for x (number of balloons):

67.50 = (4.50)x

x = 15

The total number of balloons purchased for the party is 15.

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2 years ago

72 ounces in 6 steaks

svet-max [94.6K]

12 ounces for each steak ..............

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In a litter, 2 out of 8 kittens are male. What percent of the kittens are female? * 2 points 28% 75% 82%

vladimir2022 [97]

The answer would be 28%

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3 years ago

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What is true of the data in the dot plot? Check all that apply. Number of Minutes for Each Commercial Break A dot plot going fro

Natasha2012 [34]

Answer:

The center is 3

The peak is 5

The spread is from 1 to 5.

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3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago