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stepladder [879]
3 years ago
14

I have to find the solution of the equations ​

Mathematics
1 answer:
AysviL [449]3 years ago
8 0
The solution of the equations is A) (-2,-4)
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Please answer all of them and show your work please!
sattari [20]

Answer:

br=uh

Step-by-step explanation:

u need our help 4 this homework? Just do it yourself, though i would do this for 270 points.

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2 years ago
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What is the discontinuity and zero of the function
lukranit [14]
The discontinuity are the point wherein the function is not defined. 
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set x-1=0 then the discontinuity point is at x=1.
Comptine the zeroes:
Set 3x^2+x-4=0
Compute the discriminant: 1^2-4(3)(-4)=49=7^2.
Then with quadratic formula we get the solutions:
(-1-7)/6=-8/6\\(-1+7)/6=1
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3 years ago
When two lines have the same slope they are parallel. using this statement, decide whether the two lines below are parallel or n
bearhunter [10]

Answer:

They're not parallel, because 4x and 12x are not the same slope

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3 years ago
A local hamburger shop sold a combined total of 564 hamburgers and cheeseburgers on Monday. There were more cheeseburgers sold t
GrogVix [38]

Less Than 282

Step-by-step explanation:

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5 0
3 years ago
Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t
Alina [70]

Answer:

~150=50e^{-0.01()20}

~p(100)=\$127.7

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week P_{20}=\$150

Marginal price-demand function p'(x)=-0.5e-0.01x

Generally the The Marginal price function is mathematically given by

  p'(x)=-0.5e^{-0.01x}  

  p(x)=\int-0.5e^{-0.01x}  

  p(x)=50e^{-0.001x}+C  

Therefore the equation when the demand is 20 TVs per week at $150 per TV

150=50e^{-0.01()20}

Giving

p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}

Therefore the Price when the demand is 100 TVs per week

p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}

p(100)=\$127.7

7 0
2 years ago
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