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Elan Coil [88]
3 years ago
14

Polygon ABCD will be dilated by a scale factor of 2.2 with the origin as the center of dilation, resulting in the image A′B′C′D′

. What will the slope and length of C'D' be?
m = undefined, C′D′ = 13.2 units



m = 0, C′D′ = 6.6 units



m = 0, C′D′ = 13.2 units



m = undefined, C′D′ = 8 units

Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

m = undefined, C′D′ = 13.2 units

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Let A = {1, 2, 3, 4, 5} and B = {2, 4}. What is A ∩ B? (1 point)
Rainbow [258]

Answer:

{2, 4}

Step-by-step explanation:

Intersection is the elements that two or more sets have in common. In A and B, they share {2, 4} in common.

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The scatter plot below shows the average traffic volume and average vehicle speed on a certain freeway for 50 days in 1999.
Solnce55 [7]

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As traffic volume increases, vehicle speed increases.

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The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

7 0
3 years ago
During first semester the ratio of the number of students in art class to the number of students in gym class was 2:7. However t
elena-s [515]
5/4 = 75/g....cross multiply because this is a proportion
5g = 300
g = 300/5
g = 60
so in 2nd semester, there were 75 students in art class and 60 students in gym class....for a total of 135 students.

1st semester....ratio was 2:7...added = 9
art : 2/9(135) = 270/9 = 30 <=== art class had 30
gym: 7/9(135) = 945/9 = 105 <=== gym class had 105

4 0
3 years ago
What is the domain of this function? 
hichkok12 [17]

Answer:

no real numbers

Step-by-step explanation:

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