Answer:
0.3431
Step-by-step explanation:
Here, it can work well to consider the seeds from the group of 18 that are NOT selected to be part of the group of 15 that are planted.
There are 18C3 = 816 ways to choose 3 seeds from 18 NOT to plant.
We are interested in the number of ways exactly one of the 10 parsley seeds can be chosen NOT to plant. For each of the 10C1 = 10 ways we can ignore exactly 1 parsley seed, there are also 8C2 = 28 ways to ignore two non-parsley seeds from the 8 that are non-parsley seeds.
That is, there are 10×28 = 280 ways to choose to ignore 1 parsley seed and 2 non-parsley seeds.
So, the probability of interest is 280/816 ≈ 0.3431.
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The notation nCk is used to represent the expression n!/(k!(n-k)!), the number of ways k objects can be chosen from a group of n. It can be pronounced "n choose k".
Answer:
0.36 = 36/100 = 9/25
so the simplest form is 9/25
June is correct because <span>12 is a </span>multiple<span> of both </span>3 and 4<span>.</span>
Answer:
The answer would be - 11.
Step-by-step explanation:
9 + 8 = 17
17 - 6 = 11.
4 - 5 = 4 + - 5 = - 1
11(- 1) = 11 × - 1 = - 11
Therefor, your answer would be - 11.
Hope this helps!
