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VashaNatasha [74]
3 years ago
10

The height of the tunnel at the center is 54 ft, and the vertical clearance must be 18 ft at a point 8 ft from the center. Find

an equation for the ellipse.
Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

the standard form for a horizontal ellipse is

X^2/a^2 + y^2/b^2 = 1

Substitute 54 for b and and use (8,18) as the

point to find a

x=8

y=18

8^2/a^2 + 18^2/54^2 =1

64/a^2 +  324/2916 = 1

324/2916 reduces to 1/9

64/a^2 + 1/9 = 1

64/a^2= 1-1/9

64/a^2 = 8/9

64*9/8 = a^2

576/8 = 72

A^2 = 72

A = square root(72) = 8.485

 So formula

would be x^2/72 + y^2/2916 =1

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3 years ago
I need help with elimination with substitution. The equations are 3x+4y=19 and 3x+6y=33
olganol [36]
For elimination, multiply one whole equation by negative one (-1), then add or subtract according to your signs. After that, it will be a one-step equation.

3x + 4y = 19          3x + 4y = 19             3x + 4y = 19          -2y = -14        y = 7
3x + 6y = 33     -1 (3x + 6y = 33)          -3x - 6y = -33          -14 / -2

Then you would go back and substitute the value of (y) back into either equation and then solve for the remaining variable (x). Finally, use both values to make an ordered pair.

3x + 4y = 19          3x = -9          x = -3          (-3 , 7)
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4 0
3 years ago
Math 15
avanturin [10]

Answer:

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Step-by-step explanation:

<u>Area of rhombus is:</u>

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<u>We have:</u>

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  • q = 13.8 ft

<u>The area is:</u>

  • A = 18.3*13.8/2 = 126.27 ft²

Correct choice is C

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