You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number:
5^-1 = 1/5
. . . keep trying those. . .
5^-4 = 1/625
so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625
x = log₅ 5⁻⁴
log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down:
x = -4 is your answer
if the exponent dropping down doesn't make sense to you, you can think of it in another way:
x = log₅ 5⁻⁴
expand the expression so that the exponent moves in front of the log function:
x = (-4) log₅ 5
then, still, log base 5 of 5 simplifies to 1, so you're left with:
x = (-4)1 or x = -4
Answer:
5 (grandson's age now)
35 (son's age now)
60 (father's age now)
Step-by-step explanation:
Answer:
Part a) The measure of the sides of triangle DEF are
![d_D_E=\sqrt{90}\ units](https://tex.z-dn.net/?f=d_D_E%3D%5Csqrt%7B90%7D%5C%20units)
![d_E_F=\sqrt{65}\ units](https://tex.z-dn.net/?f=d_E_F%3D%5Csqrt%7B65%7D%5C%20units)
![d_D_F=\sqrt{221}\ units](https://tex.z-dn.net/?f=d_D_F%3D%5Csqrt%7B221%7D%5C%20units)
Part b) Is a scalene triangle
Step-by-step explanation:
we know that
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
we have the coordinates
D(8,-6) E(-1,-3) F(-2,5)
step 1
Find the length side DE
D(8,-6) E(-1,-3)
substitute in the formula
![d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-3%2B6%29%5E%7B2%7D%2B%28-1-8%29%5E%7B2%7D%7D)
![d=\sqrt{(3)^{2}+(9)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%283%29%5E%7B2%7D%2B%289%29%5E%7B2%7D%7D)
![d_D_E=\sqrt{90}\ units](https://tex.z-dn.net/?f=d_D_E%3D%5Csqrt%7B90%7D%5C%20units)
step 2
Find the length side EF
E(-1,-3) F(-2,5)
substitute in the formula
![d=\sqrt{(5+3)^{2}+(-2+1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285%2B3%29%5E%7B2%7D%2B%28-2%2B1%29%5E%7B2%7D%7D)
![d=\sqrt{(8)^{2}+(-1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%288%29%5E%7B2%7D%2B%28-1%29%5E%7B2%7D%7D)
![d_E_F=\sqrt{65}\ units](https://tex.z-dn.net/?f=d_E_F%3D%5Csqrt%7B65%7D%5C%20units)
step 3
Find the length side DF
D(8,-6) F(-2,5)
substitute in the formula
![d=\sqrt{(5+6)^{2}+(-2-8)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285%2B6%29%5E%7B2%7D%2B%28-2-8%29%5E%7B2%7D%7D)
![d=\sqrt{(11)^{2}+(-10)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2811%29%5E%7B2%7D%2B%28-10%29%5E%7B2%7D%7D)
![d_D_F=\sqrt{221}\ units](https://tex.z-dn.net/?f=d_D_F%3D%5Csqrt%7B221%7D%5C%20units)
step 4
Classify the triangle by the measure of its sides
we have
![d_D_E=\sqrt{90}\ units](https://tex.z-dn.net/?f=d_D_E%3D%5Csqrt%7B90%7D%5C%20units)
![d_E_F=\sqrt{65}\ units](https://tex.z-dn.net/?f=d_E_F%3D%5Csqrt%7B65%7D%5C%20units)
![d_D_F=\sqrt{221}\ units](https://tex.z-dn.net/?f=d_D_F%3D%5Csqrt%7B221%7D%5C%20units)
so
Is a scalene triangle, because is a triangle in which all three sides have different lengths.
Answer:
whats the question
Step-by-step explanation: