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user100 [1]
3 years ago
11

I need help asap with this iready lesson!!!!

Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

top left

Step-by-step explanation:

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The graph shown compares the rent Andrew and Dave pay for renting bikes from different stores
Dmitry_Shevchenko [17]

Answer:I don’t know either

Step-by-step explanation:

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3 years ago
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I need help with this one .
skelet666 [1.2K]

Answer:

32/9

Step-by-step explanation:

2 to the fifth power is 32. 3 to the second power is 9.

3 0
2 years ago
Select ALL the correct answers.
IgorC [24]

Answer:

A. 4(x - 4) + 2(3x² + 3x - 20)

C. (11x² + 7x - 55)-(5x² - 3x + 1)

F. (3x² + 5x - 28) + (3x² + 5x - 28)

Step-by-step explanation:

Given:

(3x-7)(2x+8)

= 6x² + 24x - 14x - 56

=6x² + 10x - 56

A. 4(x - 4) + 2(3x² + 3x - 20)

= 4x - 16 + 6x² + 6x - 40

= 6x² + 10x - 56

B. (3x² + 5x - 28) - (2x² + 4x + 28)

= 3x² + 5x - 28 - 2x² - 4x - 28

= x² + x - 56

C. (11x² + 7x - 55)-(5x² - 3x + 1)

= 11x² + 7x - 55 - 5x² + 3x - 1

= 6x² + 10x - 56

D. 4(x - 4) - 2(3x² + 3x - 20)

= 4x - 16 - 6x² - 6x + 40

= - 6x² - 2x + 24

E. (11x² + 7x - 55)-(5x² - 3x + 2)

= 11x² + 7x - 55 - 5x² + 3x - 2

= 11x² - 5x² + 7x + 3x - 55 - 2

= 6x² + 10x - 57

F. (3x² + 5x - 28) + (3x² + 5x - 28)

= 3x² + 5x - 28 + 3x² + 5x - 28

= 6x² + 10x - 56

7 0
2 years ago
What three dimensional solid has 6 rectangular faces, 2 equal bases that are not rectangles, and 18 edges
lapo4ka [179]

A hexagonal prism should work! The two bases are hexagons, and there are 6 lateral faces that are rectangles. When you count the edges, there are 18

5 0
2 years ago
Read 2 more answers
Multiply and simplify: –3x2y2 • x4<br> –3x5y2<br><br> 9x5y2<br><br> –3x6y2<br><br> –3x5y6
Contact [7]

Answer:

Multiplying and simplifying the term -3x^2y^2 \:.\: x^4 we get \mathbf{-3x^6y^2}

Option C is correct option.

Step-by-step explanation:

We need to multiply and simplify: -3x^2y^2 \:.\: x^4

Simplifying the term:

-3x^2y^2 \:.\: x^4

While multiplying, the variables with same bases are multiplied: a^m\:.\:a^n=a^{m+n}

In the given question only x^2 and x^4 are variables with same bases, So we get:

=-3(x^{2+4})y^2\\=-3x^6y^2

So, multiplying and simplifying the term -3x^2y^2 \:.\: x^4 we get \mathbf{-3x^6y^2}

Option C is correct option.

4 0
3 years ago
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