3 years ago

I need help asap with this iready lesson!!!!

Mathematics

1 answer:

Ksju [112]3 years ago

8 0

Answer:

top left

Step-by-step explanation:

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The sum of the first three terms of geometric sequence is 14. If the first term is 2, find the possible values of the sum of the

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Geometric series are in the form of

$a +a*r +a*r^2+...$

Where a is the first term and r is the common ratio .

And it is given that

$2 +2*r +2*r^2=14$

$2r^2+2r-12=0$

$r^2 +r-6=0$

$(r+3)(r-2)=0$

r=-3,2

So the first five terms are

$2+2(-3)+2(-3)^2+2(-3)^3+2(-3)^4 or 2+2(2)+2(2)^2+2(2)^3+2(2)^4$

= 2-6+18-54+162 or 2+4+8+16+32

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3 years ago

2X+15= -3x how do you work this equation

Sphinxa [80]

Answer: $x=-3$

Add 3x to both sides

$2x+15+3x=-3x+3x\\5x+15=0$

Subtract 15 from both sides

$5x+15-15=0-15\\5x=-15$

Divide both sides by 5

$5x/5=-15/5\\x=-3$

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