I think it’s D, sorry if I’m wrong.
Let x,y be the two numbers.
Given that one number is 8 greater than another.
Let x be the smaller number ans y be the greater number.
That is y=x+8. Let this be the first equation.
And also given that product of the two numbers is 84.
That is x × y = 84, let us plugin y=x+8 here.
x × (x+8) = 84
x²+ 8x -84 = 0.
x²+12x-4x-84 = 0
x(x+12)-4(x+12) =0
(x-4)(x+12)=0
That is x= 4 or -12.
<h3>If x=4 , y= 4+ 8 = 12</h3>
<h3>If x= -12, y= -12+8 = -4 </h3>
Hence two positive numbers corresponding to given conditions are 4,12.
And two negative numbers corresponding to given conditions are -12,-4.
Step-by-step explanation:
hope it may help you!!
please mark as brainlist please (´;︵;`)
2/sqrt 5
by rationalising the denominator,
2/sqrt 5 × sqrt 5/sqrt 5
= 2(sqrt 5)/sqrt 5(sqrt 5)
= 2 sqrt 5/5
-
hope this helps! :))))
The answer is B)
x2+2x−3=0
Factor left side of equation.
(x−1)(x+3)=0
Set factors equal to 0.
x−1=0 or x+3=0
x=1
or
x=−3
