Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Answer: The last one - 5 1/3 divided by 1/6
Step-by-step explanation:
since you are trying to figure out how much she runs a day, u divide
Hope this helps :)
Answer:
k = 4/5
Step-by-step explanation:
First, rewrite 5/6k as (5/6)k; this is "five sixths of the variable k."
Next, identify the LCD. It is 6. Then the given equation becomes
5k + 4 = 8
Consolidate the constant terms:
5k = 4
Solve for k: k = 4/5
Answer:
take 361times 3.14
Step-by-step explanation:
you will get the answer
Answer:
x=7 y=3
Step-by-step explanation:
-x+6y=11
2x-3y=5
-2x+12y=22
2x-3y=5
Add both equations
-2x+2x-3y+12=22+5
9y=27
y=3
plug y back in
-x+18=11
-x=-7
x=7
