1/5 five being the denominator, because in math you must always simplify
Answer: 49
Step-by-step explanation:
From your question, I think you mean the largest number. The answer is given below.
Let the five consecutive odd numbers be:
a, a+2, a+4, a+6 and a+8.
Thee sum of the first and double the last is 139. This can be written as:
a + 2(a+8) = 139
a + 2a + 16 = 139
3a + 16 = 139
3a = 139 - 16
3a = 123
a = 123/3
a = 41
The first number = 41
The largest number = a+8 = 41 + 8 = 49.
Your anwer is C)<span>f(x) = 467(5 to the one fourth power)4x</span>
