Which expression is equivalent to 1+ 2(x - 1)?

Mathematics

1 answer:

leonid [27]3 years ago

4 0

Answer:

i dont know what the answers to the question is so i think its 2x-1 off of what i know

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A major advantage of longitudinal design over the cross-sectional design is the ability to detect change as a result of repeated

Alex73 [517]

Answer:

Conclusion: The statement is true.

Step-by-step explanation:

A longitudinal design consists of the observation of one or several variables in a group of individuals during a time window, in order to record the possible changes that are generated in said characteristic in that lapse.

On the other hand, the transverse design is concerned with measuring one or several variables at a single point of time and, therefore, does not allow changes to be detected over time.

Conclusion: The statement is true.

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=6%2F5%20%28cos%28120%29%20%2B%20isin%28120%29%29%203%2F5%20%28cos%2845%29%20%2B%20i%20sin%2845

marysya [2.9K]

The product is equal to:

$\frac{18}{25}(cos(165) + i*sin(165))$

<h3>How to solve the product?</h3>

Remember that we can write a complex number in polar form as:

$R*e^{i*a} = R*(cos(a) + i*sin(a))$

Then the given product:

$\frac{6}{5}*(cos(120) + i*sin(120))*\frac{3}{5}*(cos(45) + i*sin(45))$

can be rewritten to:

$(\frac{6}{5}*e^{i*120})*(\frac{3}{5}*e^{i*45})$

Now is easier to solve the product:

$(\frac{6}{5}*e^{i*120})*(\frac{3}{5}*e^{i*45})\\\\= \frac{6}{5} *\frac{3}{5} *e^{i*(120 + 45)}\\\\= \frac{18}{25}*e^{i*165}\\\\= \frac{18}{25}(cos(165) + i*sin(165))$