Answer:
∠ EFH = 112°
Step-by-step explanation:
∠ ACD and ∠ EFH are Alternate exterior angles and are congruent, thus
11x - 20 = 9x + 4 ( subtract 9x from both sides )
2x - 20 = 4 ( add 20 to both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Thus
∠ EFH = 11x - 20 = 11(12) - 20 = 132 - 20 = 112°
Answer:
x = 40
Step-by-step explanation:
The ADF is 90 degrees so the CAF will also be 90
So you do
( x + 15 ) + 90 + 35 = 180
x + 15 + 90 + 35 - 90 = 180 -90
x + 15 + 35 = 90
x + 15 + 35 - 35 = 90 - 35
x + 15 = 55
x + 15 - 15 = 55 - 15
x = 40
F(x)= 9x^3 + 2x^2 - 5x + 4
g(x)= 5x^3 - 7x + 4
f(x) - g(x)
9x³ + 2x² - 5x + 4 - (5x³ - 7x + 4)
9x³ + 2x² - 5x + 4 - 5x³ +7x - 4
9x³ - 5x³ + 2x² -5x + 7x + 4 - 4
4x³ + 2x² + 2x
Answer:
15c+12y
Step-by-step explanation:
6c + 7c + 5y + 2c + 7y
13c+2c +12y
15c+12y
have a great day!
