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maxonik [38]
3 years ago
14

Find the amount of simple interest earned for depositing the given principle in an account if $2200 is invested at 5.5 %

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
3 0

Answer: $726 in interest is accumulated over a period of 6 months

Tema [17]3 years ago
3 0

Answer:

  $60.50

Step-by-step explanation:

Put the given numbers into the formula and do the arithmetic. 6 months is 1/2 year.

  i = Prt . . . . i is interest earned, P is principal amount, r is annual rate, t is number of years

  i = $2200×0.055×0.5 = $60.50

The amount of simple interest earned in 6 months is $60.50.

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A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.
madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X  ≥  65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean (\mu_x) = 64  and a standard deviation (\sigma_x) = \frac{19}{\sqrt{14} }

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x} but μ=64 and σ=19 and n=14,  \mu_x=\mu=64 and \sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }

Therefore: z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X  ≥  65.6)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x}

Therefore: z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32

From z table,  P(X  ≥  65.6) =  P(z  ≥  0.32) = 1 -  P(z  <  0.32) = 1 - 0.6255 = 0.3745

P(X  ≥  65.6) = 0.3745

P(X < 68.2) = 0.7967

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