They are finite, They are finite because they are able to be multiplied multiple times.
Hello! And thank you for your question!
Use Pemdas to get
3^(n+2)*4=3^28
Rewrite the equation:
3^4(n+2) = 3^28
Cancel the base of 3:
4(n + 2) = 28
Then divide 4 on both sides:
2 + n = 28/4
Simplify 28/4:
2 + n = 7
Subtract 2 on both sides:
n = 7 - 2
Finally simplify 7 - 2:
n = 5
Final Answer:
n = 5
Answer:5
Step-by-step explanation:
3 | 1 5 -8 6
. | 3 24 48
- - - - - - - - - - - - - - - -
. | 1 8 16 54
That is to say,
The remainder is 54.
Another way of doing it is to apply the polynomial remainder theorem, which says the remainder upon dividing a polynomial 
by 
is exactly 
. So recognizing that the listed coefficients refer to
we find
Answer:
ponienue bene sumui nokjhvbkkznnuebdjdvkllteumhhnslsgsnnjjjhjjjjjñahyteneiungrenshdkaubsujajjajaajanananaishzuxnsijponiuLÑhKsljnsy kxn
