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2 years ago

6

Paul high earns $5.00 an hour working part-time at an auto parts store he work 16 hours per week. What is his gross pay each wee

k

1 answer:

Nataly [62]2 years ago

6 0

Answer:

$80

Step-by-step explanation:

$5 per hour, then for 16houurs. 5*16=80

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2 years ago

Which equation shows the distributive property?

atroni [7]

Do u have a pic of the problem ?

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2 years ago

Graph the linear equation in three plots: -x+2y=11

MariettaO [177]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

Convert the given equation to the form y = mx + b:

$-x+2y=11$ <em>add x to both sides</em>

$2y=x+11$ <em>divide both sides by 2</em>

$y=\dfrac{1}{2}x+\dfrac{11}{2}$

It's a linear function.

We need only two points to plot the graph. Select any two x values, insert into the equation and calculate y values.

for x = 1

$y=\dfrac{1}{2}(1)+\dfrac{11}{2}=\dfrac{1}{2}+\dfrac{11}{2}=\dfrac{12}{2}=6\to(1,\ 6)$

for x = -5

$y=\dfrac{1}{2}(-5)+\dfrac{11}{2}=-\dfrac{5}{2}+\dfrac{11}{2}=\dfrac{6}{2}=3\to(-5,\ 3)$

3 0

2 years ago

This is solving differential equations by sepeartion of variables

Brums [2.3K]

$\mathrm dy+k(y-70)\,\mathrm dx=0$

Separating variables gives

$\dfrac{\mathrm dy}{y-70}=-k\,\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dy}{y-70}=-k\int\mathrm dx$
$\ln|y-70|+C_1=-kx+C_2$
$\ln|y-70|=-kx+C$

Solving for $y$ gives

$e^{\ln|y-70|}=e^{-kx+C}$
$y-70=e^{-kx}e^C$
$y=Ce^{-kx}+70$

As $y(1)=140$ , you get

$140=Ce^{-k}+70$
$70=Ce^{-k}$
$C=70e^k$

so the particular solution to this ODE is

$y=70e^ke^{-kx}+70$
$y=70e^{k(1-x)}+70$

Unless you have any more information, you're done.

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2 years ago

Use substitution to solve the system<br><br> {y=2x-4<br> {6x+4y=12

Luba_88 [7]

Answer:

(2,0)

x=2 and y=0

Step-by-step explanation:

Hope this helps

6 0

2 years ago