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dusya [7]
3 years ago
10

Suppose that IQ scores have a bell-shaped distribution with a mean of 105 and a standard deviation of 15. Using the empirical ru

le, what percentage of IQ scores are
greater than 120? Please do not round your answer.
Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

Answer to Suppose that IQ scores have a bell-shaped distribution with a mean of ... Question: Suppose That IQ Scores Have A Bell-shaped Distribution With A Mean Of 105 And A Standard Deviation Of 15. ... Please Do Not Round Your Answer. ... Using the empirical rule, what percentage of IQ scores are greater than 120?Step-by-step explanation:

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What is the domain and range of the relation shown in the table?
seropon [69]

Answer:

domain: {2, -1, 5, -3}

range: {2, 4, 2, 0}

Step-by-step explanation:

domain : of all the input values shown on the x-axis.

range : the set of possible output values shown on the y-axis.

7 0
3 years ago
10. The area of a square frame is 55 square inches. Find the length of one side of the
Amanda [17]

Answer:

see explanation

Step-by-step explanation:

The area (A) of a square is calculated as

A = s² ( s is the side length )

Given A = 55 , then

s² = 55 ( take the square root of both sides )

s = \sqrt{55} ≈ 7 in ( to the nearest whole inch )

s ≈ 7.4 in ( to the nearest tenth of an inch )

6 0
3 years ago
Read 2 more answers
Write a numerical expression that represents the sum of nine squared and 35
garri49 [273]
The numerical expression would be -- nine squared which is 81, and 35 so you could put nine to the second power plus 35, or the full completed answer would be 116.
3 0
3 years ago
The number 320 million written in scientific notation would be _____.
lisabon 2012 [21]
The scientific notation: a\cdot10^n\ where\ 1\leq a < 10\ and\ n\in\mathbb{Z}

320\ milion=320\cdot1,000,000=320\cdot10^6=3.2\cdot10^8

Answer: B. 3.2 × 10^8
6 0
3 years ago
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Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

4 0
3 years ago
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