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2 years ago

Lines AB and CD are straight lines. Find x and y. Give reasons to justify your solutions. I need both answers.

Mathematics

1 answer:

Kazeer [188]2 years ago

4 0

Answer:

1) x = 14°, y = 5°

2) x = 18.5°, y = 37°

Step-by-step explanation:

1) ∠AOC and ∠BOD are vertical angles, then ∠BOD = 25°

∠MOD = ∠MOB + ∠BOD = 90°

3x + 23° + 25° = 90°

3x = 90° - 23° - 25°

x = 42°/3

x = 14°

∠LOB = ∠LOM + ∠MOB = 90°

5y + 3x + 23° = 90°

5y = 90° - 23° - 3(14°)

y = 25°/5

y = 5°

2) ∠AOC and ∠BOD are vertical angles, then ∠BOD = 16°

∠EOB = ∠EOD + ∠DOB = 90°

2y + 16° = 90°

y = (90° - 16°)/2

y = 37°

∠DOF = ∠BOF + ∠DOB = 90°

4x + 16° = 90°

x = (90° - 16°)/4

x = 18.5°

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Question 4 please. I will mark brainliest!! i would at least like the equation of the graph thank you

Anestetic [448]

Answer:

a. -3 < x ≤ 5

b. -3 ≤ y < 3

c. (0, 0)

d. x = -3, x = 1, x = 5

e. -3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. (-1, -1), and (3, -3)

Step-by-step explanation:

a. The domain of a function is the set of the possible independent variable values which is -3 < x ≤ 5

b. The range of a function is the set of the possible values of the dependent variable which is -3 ≤ y < 3

c. The y-intercept is the point the graph crosses the y-axis

The y-intercept in the graph is the point (0, 0)

d. f(x) ≥ 0 when x = -3, x = 1, x = 5

f(x) ≥ 0 over the following range; -3 < x ≤ - 1.5, 0 ≤ x ≤ 1.5, 4.5 ≤ x ≤ 5

e. The intervals over which f(x) is decreasing are;

-3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. The local minimums where f(x) has the minimum values are;

(-1, -1), and (3, -3)

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2 years ago

What is the equation of the line that passes through the point (2, -6) and has a<br> slope of – 3\2?

Elza [17]

Answer: 4

Step-by-step explanation:

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3 years ago

What is 4 square root 7^3 in exponential form?

Gnesinka [82]

Answer:

Given the radical form: $4\sqrt{7^3}$

Use the exponent rules:

$\sqrt[n]{a^m} = (a^m)^{\frac{1}{n}} = a^{\frac{m}{n}}$

we can write $\sqrt{7^3}$ as:

$\sqrt{7^3} = (7^3)^{\frac{1}{2}} = 7^{\frac{3}{2}}$

then;

$4\sqrt{7^3}$ = $4 \cdot 7^{\frac{3}{2}}$

Therefore, $4\sqrt{7^3}$ in exponential form is $4 \cdot 7^{\frac{3}{2}}$

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3 years ago

Read 2 more answers

Which answer, to the correct number of significant figures, is closest to the true value of the expression: (9.1 x 104 )(1.1 x 1

DIA [1.3K]

Answer : The correct answer is, -13000 g

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The given expression is:

$(9.1\times 10^4)(1.1\times 10^{-5})(\log 10^{-13})(1000)g$

As we know that,

$\log 10^{-13}=-13$

$\Rightarrow (9.1\times 10^4)(1.1\times 10^{-5})(-13)(1000)g$

$\Rightarrow -13013g$

True value means, the rounding off the number. So,

$\Rightarrow -13000g$

Therefore, the correct answer is, -13000 g

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3 years ago

Two cards are chosen from a pack of cards without replacement. Calculate the probabilities: (a) Both are picture cards. (b) Both

vovangra [49]

Answer:

A) 0.0498

B)0.2451

C) 0.2549

Step-by-step explanation:

Total number of cards N = 52

A) Number of picture cards including the king, Queen ,jack = 12

P(picture cards) = (12/52)*(11/51)

P(picture cards) = 0.0498

B) Number of red cards ( hearts and diamonds) = 26

P( red cards) = (26/52)*(25/51)

P(red cards) = 0.2451

C) Number of black cards ( Spaders and clubs) = 26

P( one red and one black cards) = (26/52)*(26/51) = 0.2549

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2 years ago