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AVprozaik [17]
3 years ago
7

Given: AB≅ BC and AK ≅ KC, ∠AKE ≅ ∠CKP, Prove: ∆AKE ≅ ∆CKP PLEASE HELP!!!!!!!!!!!!!

Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

Answer:

Step-by-step explanation:

Given:

AB ≅ BC

AK ≅ KC

∠AKE ≅ ∠CKP

To Prove:

ΔAKE ≅ ΔCKP

         Statements                               Reasons

1). AB ≅ BC                                          1). Given

2). ∠BAC ≅ ∠BCA                              2). Property of Isosceles triangles

3). ∠EKA ≅ ∠PKC                               3). Given

4). ΔAKE ≅ ΔCKP                               4). ASA Postulate of congruence

Hence ΔAKE ≅ ΔCKP.

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kumpel [21]

Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3>k =  \frac{21}{80}</h3>

So the formula for the variation is

<h2>p =  \frac{21}{80} T</h2>

when

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Substitute it into the above formula

That's

p =  \frac{21}{80}  \times 500

Simplify

The final answer is

<h3>p = 131.25</h3>

Hope this helps you

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