Given: AB≅ BC and AK ≅ KC, ∠AKE ≅ ∠CKP, Prove: ∆AKE ≅ ∆CKP PLEASE HELP!!!!!!!!!!!!!
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The absolute value, or modulus, of a number is its distance from zero, or essentially its magnitude.
The absolute value produces a positive answer.
We have this definition for the absolute value, taking into account its different values for different signs:
Thus, for
, we split the absolute value as such:
and 
We solve each case.
and 
We check these solutions.
and
The absolute value produces a positive answer.
We have this definition for the absolute value, taking into account its different values for different signs:
Thus, for
We solve each case.
We check these solutions.
and
The equivalent expression of is
The expression is given as:
1 minus StartFraction 1 Over x EndFraction divided by 2
Rewrite properly as:
Express the division as product
Evaluate the product
Take the LCM
Hence, the equivalent expression of is
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