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d1i1m1o1n [39]
3 years ago
9

Simplify: 4a - (-3b) + (-2c)

Mathematics
2 answers:
777dan777 [17]3 years ago
6 0

Answer: 4a+3b-2c

this is the answer

Pavlova-9 [17]3 years ago
6 0
it would be 4a+3b-2c
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Factor 18s-63<br> A 9(2s+7)<br> B 6(3s-11)<br> C 18(s-3)<br> D 9(2s-7)
Lunna [17]

Answer:

it's D

Step-by-step explanation:

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6 0
2 years ago
?<br><br>2 to the 3rd power - 5 x (6 + 4) ÷ 2<br><br>show your work​
Delvig [45]

Answer:

-17

Step-by-step explanation:

2^3 - 5 * (6 + 4) ÷ 2

Following PEMDAS, we must focus on the parenthesis first.

2^3 - 5 * (6 + 4) ÷ 2

2^3 - 5 * (10) ÷ 2

Now we will focus on the exponent:

2^3 - 5 * 10 ÷ 2

8 - 5 * 10 ÷ 2

Now Multiplication/Division.

This is where you must follow the order in the equation where you see the multiplication sign first, so you multiply first.

8 - 5 * 10 ÷ 2

8 - 50 ÷ 2

Next, Divide:

8 - 50 ÷ 2

8 - 25

Subtract:

8 - 25

-17

2^3 - 5 * (6 + 4) ÷ 2 = -17.

4 0
3 years ago
Read 2 more answers
Use the variable x to write the phrase in symbols.
Rudik [331]

Answer:

155 + x^{3} + 14

Step-by-step explanation:

The variable x would represent the number/value we don't know, and in this case, we don't know what number is raised to the third power. This being said, x would represent that number.

The question, although worded a bit confusingly, asks to add 155, the number (x) to the exponent of 3, and 14. Mathematically, this would be 155 + x^{3} + 14.

6 0
2 years ago
Can you help me?
Semenov [28]

Answer:

0=0

Step-by-step explanation:

8 0
2 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
2 years ago
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