B is the answer
i simplified the theorem, but i hope this makes sense!
Answer:
a_{n} = a_{1} + (n-1)d
a_n = the nᵗʰ term in the sequence
a_1 = the first term in the sequence
d = the common difference between terms
The general term of an arithmetic sequence can be written in terms of its first term a1, common difference d, and index n as follows: an=a1+(n−1)d. ... The nth partial sum of an arithmetic sequence can be calculated using the first and last terms as follows: Sn=n(a1+an)2.
Given:
The equations are


To find:
Which function is changing more quickly.
Solution:
The slope intercept form of a line is

Where m is slope and b is y-intercept.
On comparing
with the slope intercept form, we get



On comparing
with the slope intercept form, we get


Since,
, it means the absolute rate of change of second function is greater than the first function.
Therefore, the second function is changing more quickly.
The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Data;
- Angle = 30 degree
- Opposite = 35
- Adjacent = x
<h3>Trigonometric Ratio</h3>
Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.
SOHCAHTOA
Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.

The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Learn more on trigonometric ratio here;
brainly.com/question/12172664