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2 years ago

Solve the system of equations

Mathematics

2 answers:

vladimir1956 [14]2 years ago

6 0

Answer= A

This is because you have to turn one of the equations to a negative.

nikitadnepr [17]2 years ago

5 0

The solution is A

x=2 y=-1

the solution is where the two lines intersect

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(-2) + (3 - 7)<br> (-1) * (-2)

valentinak56 [21]

Answer:

-6
2

Step-by-step explanation:

$( - 2) + ( 3 - 7)$

$- 2 + (3 - 7)$

$- 2 + - 4$

$- 2 - 4$

$\boxed{\green{ = - 6}}$

◇◇•◇◇

$( - 1) \times ( - 2)$

$1 \times 2$

$\boxed{\green{= 2}}$

4 0

3 years ago

I really need help with this dividend thing. Plz help ASAP

dimaraw [331]

Answer:

45.26

Step-by-step explanation:

$36.50 \times 73 = (2664.5) \div 50 \\ = 53.29$

$53.29 \times 62 = (3303.98) \div 73 \\ = 45.26$

4 0

3 years ago

Layla borrowed some money from her friend in order to help buy a new video game

astra-53 [7]

Answer:

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8 0

2 years ago

Simplify: 4w(to the power of 9)+(-2w(to the power of 9)) enter the original expression if it cannot be simplified

igomit [66]

4w⁹ -2w⁹
= (4-2)w⁹ . . . . . distributive property, or "collecting terms"
= 2w⁹

_____
In plain text, a caret (^) is used to identify an exponent. w⁹ = w^9. If the exponent has any arithmetic, you need parentheses around it. w^(8+1)

6 0

3 years ago

The Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging

kirza4 [7]

Answer:

Step-by-step explanation:

given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging

Clerk I II III total

Pack 0.33 0.23 0.44 1

Defective 0.02 0.025 0.015

Pack&def 0.0066 0.00575 0.0066 0.01895

a) probability that a randomly selected box of chocolates was packed by Clerk 2 and does not contain any defective chocolate

= P(II clerk) -P(II clerk and defective) = $0.23-0.00575=0.22425$

b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)

=0.01895

c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3

=P(clerk 3 and def)/P(defective)

= $\frac{0.0066}{0.01895} \\=0.348285$

8 0

3 years ago

Solve the system of equations￼

Solve the system of equations