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Radda [10]
3 years ago
8

Hello can I have some help with this expand question 4(z+2)+4(z+3)

Mathematics
2 answers:
Gekata [30.6K]3 years ago
7 0

Answer:

4(2z + 5)

Step-by-step explanation:

4(z + 2)+4(z + 3) =

= 4z + 8 + 4z + 12

= 8z + 20

= 4(2z + 5)

wel3 years ago
4 0

Step-by-step explanation:

4(z+2)+4(z+3)

=4z+8+4z+12

=8z+20

by simplifying-

=2z+5

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4 0
3 years ago
Let f(x)=x^2- 3. 1. Show that [0, 2] is a bracketing interval for f 2. Carry out 3 iterations of the bisection method applied to
Papessa [141]

Answer:

root estimate = 1.75

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Step-by-step explanation:

f is a polynomial, so it is continuous in R (real numbers). Then you can use Bolzano's theorem.

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In the bisection method you generate a sequence x_n of approximations of a root. If you have a bracketing interval [a, b], such that

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f(0)

Then:

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3 0
3 years ago
5 (5x6)+(8x9)+6=? 2(5x8)+(8x28)+9
KonstantinChe [14]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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vekshin1
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5 0
3 years ago
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k = 45/40 
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y = 1.125x 

y will increase by 1.125 interval of x. 


5 0
3 years ago
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