Answer:
<h2>
A. ¹²/₅</h2>
Step-by-step explanation:
There is no solution for system of equations:
if: ![a_1=a_2\quad and\quad b_1=b_2\quad and\quad \bold{c_1\ne c_2}](https://tex.z-dn.net/?f=a_1%3Da_2%5Cquad%20and%5Cquad%20b_1%3Db_2%5Cquad%20and%5Cquad%20%5Cbold%7Bc_1%5Cne%20c_2%7D)
so first, we we need to transform the equations to the form where the coefficients at y will be the same:
![kx-3y=4\\ 4x-5y=7\\\\ (kx-3y)\cdot5=4\cdot5\\ (4x-5y)\cdot3=7\cdot3\\\\ 5kx-15y=20\\ 12x-15y=21](https://tex.z-dn.net/?f=kx-3y%3D4%5C%5C%204x-5y%3D7%5C%5C%5C%5C%20%28kx-3y%29%5Ccdot5%3D4%5Ccdot5%5C%5C%20%284x-5y%29%5Ccdot3%3D7%5Ccdot3%5C%5C%5C%5C%205kx-15y%3D20%5C%5C%2012x-15y%3D21)
Now we have b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂
5k = 12
÷5 ÷5
k = ¹²/₅
Answer:
The answer would be function 2.
Step-by-step explanation:
I found this out by plugging in 0 into x. What I got then was one. So I found that function 2 has a spot on 0, 1. that is how I got the answer.
Brainliest would be appreciated.
I = Prt, where P = $1,295; r = 7/100 = 0.07, t = 180/365
I = 1,295 x 0.07 x 180/365 = $44.70
Answer:
4y + 36
Step-by-step explanation:
4 × y = 4y
4 × 9 = 36
4y + 36
Answer:
138
Step-by-step explanation:
6(52)−(5)(4)+8
=(6)(25)−(5)(4)+8
=150−(5)(4)+8
=150−20+8
=130+8
=138