Answer:
do you want us to answer all of them?
Step-by-step explanation:
Answer:
(a)x=128 degrees
(b)![\angle APD\neq 116^\circ](https://tex.z-dn.net/?f=%5Cangle%20APD%5Cneq%20116%5E%5Ccirc)
Step-by-step explanation:
![\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ](https://tex.z-dn.net/?f=%5Cangle%20ABD%2B%5Cangle%20CBD%20%3D180%5E%5Ccirc%24%20%28Linear%20Postulate%29%5C%5C%5Cangle%20ABD%2B116%5E%5Ccirc%20%3D180%5E%5Ccirc%5C%5C%5Cangle%20ABD%3D180%5E%5Ccirc-116%5E%5Ccirc%5C%5C%5Cangle%20ABD%3D64%5E%5Ccirc)
(a) Now:
![\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ](https://tex.z-dn.net/?f=%5Cangle%20AOD%3D2%20%5Ctimes%20%5Cangle%20ABD%24%20%28Angle%20at%20the%20centre%20is%20twice%20the%20%20angle%20at%20the%20circumference%29%5C%5Cx%3D2%20%5Ctimes%2064%5E%5Ccirc%5C%5Cx%3D128%5E%5Ccirc)
(b)
![\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ](https://tex.z-dn.net/?f=%5Cangle%20APD%3D2%20%5Ctimes%20%5Cangle%20ABD%24%20%28Inscribed%20Angle%20Theorem%29%5C%5C%5Cangle%20APD%3D2%20%5Ctimes%2064%5E%5Ccirc%5C%5C%20%5Cangle%20APD%3D128%5E%5Ccirc)
![\angle APD\neq 116^\circ](https://tex.z-dn.net/?f=%5Cangle%20APD%5Cneq%20116%5E%5Ccirc)
5/6 is closest to 1 because it it 1/6 away from 1 and is 5/6 away from 0 and is 2/6 away from 1/2 (referring 1/2 as 3/6) Hope this helps!
Angles 1 and 3, angles 2 and 4, angles 5 and 7, and angles 6 and 8. They are also congruent, because vertical angles are congruent.
Kelly should get back $6.72.
To get this answer, start by adding 16.79 and 28.49. The answer you should get is 45.28. Next, subtract 45.28 from 50 and your total should be 6.72. Hope this helped!