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3 years ago

PLEASE SOMEONE HELP I TRULY DO NOT UNDERSTAND

Mathematics

1 answer:

IceJOKER [234]3 years ago

7 0

Hi there!

$\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }$

$f(x) = 9x^{3} - 4$

Find the inverse by replacing f(x) with y and swapping the x and y variables:

$x = 9y^{3} - 4$

Isolate y by adding 4 to both sides:

$x + 4 = 9y^{3}$

Divide both sides by 9:

$\frac{x+4}{9}= y^{3}$

Take the cube root of both sides:

$y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }$

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I don’t know how to do this one. could someone help

DedPeter [7]

Answer:

If it is being dilated from (0,0) the answer is below.

Step-by-step explanation:

It depends on where it is scaled from. If you choose a point directly to that points left it will be pushed tot he right, and vice versa if it is on its right. Same for above and below

I am going to assume we are dilating from (0,0), but again, if there is another part of the question saying where it's from use this method for that as well.

So, from (0,0) the initial point is (-3, 11) Scaling by a factor of 3 means it gets pushes AWAY so it is 3 times as far away. (If it were a fraction or decimal it would be getting pulled closer)

Using (0,0) as the dilation point is the easiest because we just have to ask how far are the x and y coordinates away from (0,0) and any number is THAT number away from 0.

We break this into the two coordinates too. so how far is -3 from 0? -3. so we want a point 3 times as far away, so what is that? -9. Same for 11, 11 is 11 away from 0 so we want it 3 times as far, which is 33.

Now that we have the two coordinates that is the answer.

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3 years ago

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nika2105 [10]

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3 years ago

ok more of a question not like a equation or anything but when do you know when there is a extraneous answer and how do you solv

Likurg_2 [28]

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In this case, one can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.

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1 year ago

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Step-by-step explanation:

First, find the area of the rectangle (ignoring the missing triangle inside). The area of the rectangle is its base times its height, which is 8*13=104.

Next, find the area of the triangle. The area of the triangle is its base times height, divided by two.

The width of one side of the rectangle is 13, and the width of the side of the rectangle is 8 (4 + 4). Therefore, subtract 8 from 13 and the missing section in the side of the rectangle is 5. 5 is equal to the base of the triangle.

The height of the triangle is given, which is 6. As stated before, the area of a triangle is its base times height divided by two, which is 5*6/2 in this case. The area of the triangle is equal to 15.

Now, subtract the area of the triangle from the area of the rectangle. 104-15=89.

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