Answer:
<u>-5 ± √5² - 4 · 1 · 4</u>
2 · 1
Step-by-step explanation:
ax²+bx+c=0 (quadratic equation)
x=<u> -b ± √b² - 4ac</u>
2a
a= 1
b= 5
c= 4
-<u>5 ± √5² - 4 · 1 · 4</u>
2 · 1
Answer:
Point on Midline (0,3)
Maximum (9π/2,3)
Minimum (-9π/2,-3)
Step-by-step explanation:
in the given sine function which is in the form of f(x) = a sin(bx+c) +d
a = amplitude
period = frequency = 18π
Therefore b = 2π/18π = 1/9
Y intercept = vertical shift = 3
Horizontal shift = d = 0
Therefore the sine function will be
f(x) = 6 sin(x/9) + 3
Now first point on the midline is (0,3)
Second point is maximum (9π/2,9)
Third point be a minimum value ( -9π/2,-3)
Answer:
good job❤
Step-by-step explanation: