The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then





To exact form:
8/15
To decimal form:
0.53¬ repeating.
Answer:
Linear
Step-by-step explanation:
pretty self explanatory
Answer:
- y = -5/2x + 5
- y = 2x -1
- y = 24/11
- y = 4x + 4
Step-by-step explanation:
To solve for y, subtract the x-term and divide by the coefficient of y.
5x +2y = 10
2y = -5x +10
y = -5/2x + 5
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2y -4x = -2
2y = 4x -2
y = 2x -1
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7y +4y = 24
y = 24/11
We assume there is a typo, but cannot tell what it is. Use the same method as described and demonstrated for the other problems.
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-2x +1/2y = 2
1/2y = 2x +2
y = 4x +4