Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
Answer:
868 m³
Step-by-step explanation:
Volume = Difference of cones
V = ⅓(pi×r²h)
Volume of cone with base Circle O:
h = 8.2+8.2 = 16.4 m
V1 = ⅓(pi×7.6²×16.4)
V1 = 991.97
Volume of cone with base Circle A:
V2 = ⅓(pi×3.8²× 8.2)
V2 = 124 m³
Volume = V1 - V2
991.97 - 124 = 868 m³
We have been given graph of a downward opening parabola with vertex at point 
. We are asked to write equation of the parabola in standard form.
We know that equation of parabola in standard form is 
.
We will write our equation in vertex form and then convert it into standard form.
Vertex for of parabola is 
, where point (h,k) represents vertex of parabola and a represents leading coefficient.
Since our parabola is downward opening so leading coefficient will be negative.
Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:
Divide both sides by 
So our equation in vertex form would be 
.
Let us convert it in standard from.
Therefore, the equation of function is standard form would be .
Answer:
Step-by-step explanation:
Subtract the distance driven by Rohan from the total distance
Distance driven by Raj = 1245 - 412
= 833 km
