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alisha [4.7K]
2 years ago
14

PLEASE HELP ME ITS ALGEBRA THANK YOUUUU

Mathematics
1 answer:
vampirchik [111]2 years ago
3 0

Answer: 2,208$

Step-by-step explanation:

To solve this problem, simply determine how much each attendee costs by doing 960$/30attendees = 32$/attendee.  Then, simply multiply this number by 69 to get: 2,208$

Hope it helps :) and let me know if you want me to elaborate further.

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Answer:

x=1.5

or

x=1 1/2

Step-by-step explanation:

4x-7>-1

add 7 to both sides

4x=6

divide by 4 on both sides

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or

x=1 1/2

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Step-by-step explanation:

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2 years ago
In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per
Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

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Final population is, P=700,000

A population growth is an exponential growth and is modeled by the following function:

P=P_0(1+r)^x

Taking log on both sides, we get:

\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}

Plug in all the given values and solve for 'x'.

x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10

So, for x > 9.13, the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

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Step-by-step explanation:

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3 years ago
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