A minor league plays 101 games,
They win 14 more than twice as many as they lost.
How many wins and loses?
Okay, simple.
First, write a simple addition equation. In this case wins = w and losses = l.
l + w = 101.
Now, we have to figure out a way to make one of the terms the same term as the other, in this case we can change the terms of w to l.
l = l
w = 2l +14 (14 more than twice the amount)
Okay. So plug in the new amount for w.
l + 2l + 14 = 101. Great! we now have a simple equation. lets solve.
put similar terms together.
3l + 14 = 101
3l = 87
l = 29
So, we have 29 loses, and
w = 2(29) + 14
72 wins!
To check,
72 + 29 = 101, correct!
Hope this helps!
Answer:
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Step-by-step explanation:
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Answer:
1 every 2.5 feet
Step-by-step explanation:
20 divided by 8 20 being the plants 8 being the length gives u 2.5
Answer:
x = 
Step-by-step explanation:
Given
x +
+ (x - 1) = 
Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions
10x + 15 + 10(x - 1) = 8
10x + 15 + 10x - 10 = 8
20x + 5 = 8 ( subtract 5 from both sides )
20x = 3 ( divide both sides by 20 )
x = 
Answer:
using a negative facto to factor the expression will be:
- 7a+49b - 35 = -7(a-7b+5)
Step-by-step explanation:
Given the expression
- 7a+49b - 35
Rewrite -35 as 5 · 7
Rewrite 49 as 7 · 7
so
= -7a + 7 · 7b - 5 · 7
as -7 is the common factor, so factoring out
= -7(a-7b+5)
Thus, using a negative facto to factor the expression will be:
- 7a+49b - 35 = -7(a-7b+5)