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Anastasy [175]
2 years ago
12

Okay I’ve been struggling on this for like 20 min, someone Pleaseee help me

Mathematics
1 answer:
Debora [2.8K]2 years ago
4 0

Answer:

Angle M=14.25°

Step-by-step explanation:

Sin(M)=16/65

Sin^-1(16/65)=14.25°

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If a geometric sequence has a2 = 495 and a6 = 311, approximate the value of the common ratio ???? to four decimal
shtirl [24]

Answer:

r = 0.8903

Step-by-step explanation:

given,

a₂ = 495

a₆ = 311

geometric  sequence formula

                       a_n = ar^{n-1}

                       a_2 = ar^{2-1}

                       a_2 = ar...................(1)

                       a_6 = ar^{6-1}

                       a_6 = ar^5................(2)

dividing equation (2) by (1)

                     \dfrac{a_6}{a_2} = \dfrac{ar^5}{ar}

                     \dfrac{311}{495} = r^4

                     r^4 = 0.628

                     r = 0.8903

hence, the common ratio of the geometric sequence is r = 0.8903

7 0
3 years ago
If one jar of peanut butter weights 1.6 pounds, how much does 5 jars of peanut butter weight?
Lady_Fox [76]

Answer:

5 × 1.6 = 8. The answer is 8 pounds.

Step-by-step explanation:

If you multiply 5 and 1.6, you get 8.

5 0
3 years ago
Read 2 more answers
A card is chosen at random from a standard deck.
allsm [11]

Answer:

6/13

Step-by-step explanation:

There are 52 cards in a deck, and 26 of them are red. There are 2 red queens in a deck, so the probability of choosing a red card that is not a queen is 24/52 = 6/13.

7 0
2 years ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
An isosceles triangle has 2 equivalent sides. The perimeter of an isosceles triangle is 84 centimeters. The measure of one of th
Pani-rosa [81]

Well, to find your solution to this problem, I would subtract 84 from 32 = 52. I would divide the number by 2, which equals 26. So, side lengths are 32, 26, and 26. 

Or, another one is that 2 sides have the length of 32, so 32+32=64. I would subtract 84 from 64 and get 20. So, side lengths are 32, 32, and 20.

3 0
3 years ago
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