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3 years ago

14

A rectangular dog park was built with the dimensions shown. The fencing that completely surrounds the park cost $12 a yard. Each

square yard of grass sod that covers the entire park cost $8. What was the total cost for the fencing and the sod?

1 answer:

leonid [27]3 years ago

7 0

Answer:

sod- 1662.6

fencing- 807.6

all- 2470.2

Step-by-step explanation:

sod-

25.5 * 8.25 = 207.825

207.825*8= 1662.6

fencing-

8.25+8.25+25.5+25.5= 67.3

67.3*12= 807.6

fencing + sod

1662.6 + 807.6= 2470.2

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Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

so

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago

Jasper's lawn is 3/4 of an acre in size. The fertilizer bag states that 5 1/2 bags are required for 1 acre. How many bags does J

Nady [450]

Answer: $4\dfrac{1}{8}\ \text{bags}$

Step-by-step explanation:

Given

Jasper lawn is three-fourth of an acre

1 acre of land requires $5\frac{1}{2}$ bags

convert mixed numeral to fraction

$\Rightarrow 5\dfrac{1}{2}=\dfrac{11}{2}$

$\therefore 1\ \text{acre}\equiv\dfrac{11}{2}\ \text{bags}\\\\\Rightarrow \dfrac{3}{4}\ \text{acre}\equiv \dfrac{11}{2}\times \dfrac{3}{4}=\dfrac{33}{8}\ \text{bags}$

$\Rightarrow \dfrac{33}{8}\ \text{bags}=4\dfrac{1}{8}\ \text{bags}$

8 0

3 years ago

Greatest to least 0.04; 0.5; 0.021; 0.133

babymother [125]

0.5, 0.04, 0.133, 0.021

4 0

3 years ago

Read 2 more answers

What are the leading coefficient and degree of the polynomial?<br> 3u+12u'-7u* +1

xxTIMURxx [149]

Answer:

See explanation

Step-by-step explanation:

Assuming the given polynomial is

$3u + 12 {u}^{2} - 7 {u}^{3} + 1$

We then rewrite in decreasing powers of u, to get:

$- 7 {u}^{3} + 12 {u}^{2} + 3u + 1$

The leading term is

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The leading coefficient is the coefficient of the leading term.

The leading coefficient is -7.

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3 years ago

Help answer this if ya know!

blagie [28]

C) The +10 is because you already have 10 coins, that will not change. The 6x is because with each passing day, the number of coins increase by 6 (x represents days). The equation then turns into y=6x+10

Hope this helps comment for more questions :)

4 0

3 years ago