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3 years ago

13

true or false: when multiplying radicals, you multiply the radicands together and the numbers outside the radicals together

1 answer:

Dmitrij [34]3 years ago

7 0

You can only multiply numbers that are inside the radical symbols

You might be interested in

Write the equation of a line that has a slope of -3 and goes through the point (5,7).

ss7ja [257]

Answer:

The equation of the line would be D) y - 7 = -3(x -5)

Step-by-step explanation:

In order to find this, we must first start with the base form of point-slope form.

y - y1 = m(x - x1)

Now we put the slope in for m and the point in for (x1, y1)

y - 7 = -3(x - 5)

6 0

3 years ago

The university is on a bearing of 050 degrees from the stadium and 300 degrees from the hospital. Mark the position of the unive

Licemer1 [7]

Answer:

Check Explanation

Step-by-step explanation:

The map isn't available, but, one can draw this bearings with the descriptions given

Angles for bearings are usually drawn, reading from the north direction.

A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.

For the sketch on the map.

On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.

Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.

Wherever the line from the hospital meets the line from the stadium, is where the University is located.

Hope this Helps!!!!

6 0

3 years ago

If the length of the side of a square is 3×-y what is the area of the square in terms of x and y

soldier1979 [14.2K]

(3x -y)(3x-y )= 9x^2 - 6xy + y^2

5 0

3 years ago

Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0

3 years ago

How much do all the pencils inside 124 boxes cost (in $), if inside each box there are 6 pencils and 33 pencils cost $8.99. Roun

Anarel [89]

124 x 6 =744 und

$8.99 divide 33 = $0.27 each pencil
$0.27 x 744 = $200.88 (round $ 201)

7 0

3 years ago